C.GoString((*C.char)(&p.mach_name))
On Thu, Apr 30, 2020 at 1:21 PM Dean Schulze <dean.w.schu...@gmail.com>
wrote:
> This expression
>
> C.GoString(C.char*(&p.mach_name))
>
> gives this error:
>
> type _Ctype_char is not an expression
>
> On Thu, Apr 30, 2020 at 2:09 PM Bruno Albuquerque <b...@gmail.com> wrote:
>
>> Not pretty but if you are sure the array is zero-terminated, you can
>> simply cast it to the correct type:
>>
>> C.GoString((C.char*)(&p.hostname))
>>
>> (untested)
>>
>>
>> On Thu, Apr 30, 2020 at 1:06 PM Dean Schulze <dean.w.schu...@gmail.com>
>> wrote:
>>
>>> That gives this error (which I've gotten with just about everything I
>>> try):
>>>
>>> cannot use &p.mach_name (type *[25]_Ctype_char) as type *_Ctype_char in
>>> argument to _Cfunc_GoString
>>>
>>> It seems to be the fixed length of the char[] that gives cgo a problem.
>>>
>>>
>>> On Thursday, April 30, 2020 at 1:46:34 PM UTC-6, Jan Mercl wrote:
>>>>
>>>> On Thu, Apr 30, 2020 at 8:17 PM Dean Schulze <dean.w...@gmail.com>
>>>> wrote:
>>>> >
>>>> > I must be missing something pretty simple, but I have a C struct like
>>>> this:
>>>> >
>>>> > typedef struct line
>>>> > {
>>>> > char hostname[HOSTNAME_MAX];
>>>> > char ip[IP_MAX];
>>>> > ...
>>>> > }
>>>> >
>>>> > When I try to do the simple thing
>>>> >
>>>> > C.GoString(p.hostname)
>>>>
>>>> An array of a fixed size within a C struct is a value (the same as in
>>>> Go), but C.GoString expects a pointer to a C.char. Try
>>>> `C.GoString(&p.hostname)`.
>>>>
>>>> Not tested. Note that if hostname is not properly zero terminated,
>>>> your code will crash or misbehave.
>>>>
>>>> (Automatic array decay applies to C code, but not in Go.)
>>>>
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>>>
>>
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