Hey,
the `-quotes denote a "raw string literal". Escape-sequences in raw string
literals are not interpreted - that's basically their purpose. So `t2`
contains the literal two-byte sequence `\n`. You can see that in the output
of `fmt.Println`, the newline is a 10, but t2 does not contain a 10, but
a 92 ("\") and 110 ("n") instead.
If you want a raw string literal to contain an actual line-break, you have
to put a line-break (not a line-break escape sequence) into it:
https://play.golang.org/p/9DYfkVDk5RC
Hope that helps
On Fri, Aug 21, 2020 at 6:01 PM 'Guilherme Dalmarco' via golang-nuts <
golang-nuts@googlegroups.com> wrote:
> Why *bytes.IndexByte *can not find '\n' in multiline string?
>
> package main
>
> import (
> "bytes"
> "fmt"
> )
>
> func main() {
> t1 := []byte("TEST\n")
> t2 := []byte(`TEST\n`)
> t3 := byte('\n')
>
> fmt.Println(t1)
> fmt.Println(t2)
> fmt.Println(t3)
>
> fmt.Println(bytes.IndexByte(t1, t3))
> fmt.Println(bytes.IndexByte(t2, t3))
> }
>
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