On Sun, Aug 23, 2020 at 1:16 PM Denis Cheremisov
<denis.cheremi...@gmail.com> wrote:
>
> You may use something like this
>
>         value2 := *(*uint64)(unsafe.Pointer(uintptr(unsafe.Pointer(&value)) + 
> 8))
>         if value2 == 0 {
>                 return true
>         }
>
> on AMD64, should work also for any 64 bit architecture (at least I believe 
> so). Remember though this is hacky and may stop working once.

You could do that, but please don't.

Ian


> воскресенье, 23 августа 2020 г. в 22:58:51 UTC+3, Aviv Eyal:
>>
>> I was trying to show that the current behavior is confusing and that 
>> fmt.Print() needing to resort to panic-and-recover is kinda code smell, but 
>> I sorts-of convinced myself that the current behavior is right, or at least 
>> consistent.
>>
>> In my code, I got bit because I sometimes use v *Type to denote "I may or 
>> may not have a value here" (where Type is a value-type).
>> This is probably a bad practice on my behalf, because I break the Liskov 
>> substitution principle: there is a value of `*Type` that is not a valid 
>> value of `Type`, and I let this value slip by.
>>
>> In this case, `v Type` implements Stringer (i.e. valid callee for 
>> `v.String()`, but `v *Type`, in the strictest sense, does not.
>> The only reason we can write:
>>
>>     func (Type) String() string {...}
>>     v *Type = &Type{...}
>>     _ = v.String()
>>
>> and have it compile, is syntactic sugar: `v` gets implicitly de-referenced, 
>> and there's an implicit assumption that it's not nil.
>> And there's a matching syntactic sugar for converting `Type` to a `*Type`.
>>
>> So, In the code:
>>
>>     func (Type) String() string {...}
>>
>>     v *Type = nil
>>     r interface{} = v
>>     _, ok = r.(Stringer)
>>
>> What I really want to ask is "Can I, at runtime, call r.String()?", whereas 
>> the question Go answers is "Is any of `r`, `*r`, or `&r` defines .String()?" 
>> - which matches the static semantics of `r.String()`.
>>
>> So, while I should probably not use *Type as a replacement for 
>> Optional<Type>, I think it might make sense to have some operator that can 
>> determine, at run-time, if a call `r.String()` is valid (including a 
>> nil-check).
>>
>>
>> -- Aviv
>>
>> On Saturday, April 11, 2020 at 4:48:28 PM UTC+3 ren...@ix.netcom.com wrote:
>>>
>>> I agree with the OP. The usefulness of nil interfaces is pretty limited. 
>>> Show me a useful case that cant easily be implemented with non-nil 
>>> interfaces.
>>>
>>> I would argue that allowing nil interfaces causes more subtle latent bugs 
>>> and makes it harder to reason about the correctness of code when reviewing 
>>> it.
>>>
>>> It just feels wrong. I realize I’m probably in the minority here but the OP 
>>> is not alone.
>>>
>>> On Apr 11, 2020, at 8:20 AM, 'Axel Wagner' via golang-nuts 
>>> <golan...@googlegroups.com> wrote:
>>>
>>> On Fri, Apr 10, 2020 at 7:17 PM <cpu...@gmail.com> wrote:
>>>>
>>>> I realize I'm reviving an age-old discussion here and apologize for 
>>>> bringing up the undead. I happend to run into this when my application 
>>>> panicked when some interfaces where initialized with nil mock objects 
>>>> instead of being left uninitialized as in production mode.
>>>
>>>
>>> Let's imagine a world in which `foo == nil` also is true if `foo` is an 
>>> interface-value containing a nil-pointer. Let's say in this world, someone 
>>> sends a message to golang-nuts. They wrote a mock for the same code. And 
>>> since it's just a mock, they just returned static value from its methods 
>>> and didn't need to care if the pointer was nil or not. They are confused, 
>>> because the passed in this mock, but the code just assumed the field was 
>>> uninitialized and never called into their mock. What would you tell them? 
>>> Why is their confusion less valid?
>>>
>>>> This would be an example where a nil implementing fooer is never caught:
>>>>
>>>> type fooer interface {
>>>>  foo()
>>>> }
>>>>
>>>> type other struct{}
>>>>
>>>> func (o *other) foo() {} // implement fooer
>>>>
>>>> func main() {
>>>>  var f fooer
>>>>
>>>>  var p *other // nil
>>>>  f = p // it is a fooer so I can assign it
>>>>
>>>>  if f == nil {
>>>>     // will not get here
>>>>  }
>>>> }
>>>>
>>>>
>>>> My confusion comes from the point that the nil interface is apparently not 
>>>> "a nil-pointer with the correct method set" while *other is even if nil.
>>>
>>>
>>> In the code you posted, even a nil *other is a perfectly fine 
>>> implementation of fooer. You can call `(*other)(nil).foo()` without any 
>>> problems.
>>> So, as you illustrated, calling methods on a nil-pointer can be totally 
>>> fine. A nil-interface, OTOH, doesn't have any methods to call, as it 
>>> doesn't contain a dynamic value. If you write `(*other)(nil).foo()`, it is 
>>> completely clear what code gets called - even if that code *might* panic. 
>>> If you write `fooer(nil).foo()`, what code should be called in your opinion?
>>>
>>> I think it's easy to see that a nil-interface and a nil-pointer stored in 
>>> an interface are very different things. Even from first principles, without 
>>> deep knowledge of the language. And if they are obviously different, I 
>>> don't understand why you'd find it confusing that they are not the same in 
>>> this particular manner.
>>>
>>>> The above is a case where that might happen. In can be worked around but 
>>>> it is unexpected unless the programmer is deeply rooted in the language 
>>>> definition.
>>>
>>>
>>> I fully agree with that. What I *don't* agree with, is where you attribute 
>>> the problem here. You say, the problem is that the nil-check is 
>>> ill-behaved. I say that - if anything - the original nil-assignment is 
>>> ill-behaved. Having `(fooer)((*other)(nil)) == nil` be true is semantically 
>>> wrong, because by checking against `nil`, you are checking if you have a 
>>> correct implementation - and you might well have a correct implementation, 
>>> even if it's using a nil-pointer.
>>>
>>> Note, that the contained pointer being nil isn't the *only* case in which 
>>> calling the method might panic. For example, what about this code?
>>> https://play.golang.org/p/lNq0qphez7v
>>> Shouldn't the `nil`-check also catch that? After all, calling the method 
>>> panics, so it's clearly not a valid implementation - even if x itself is 
>>> not nil. Why is a nil-pointer more special than any other value that causes 
>>> a method to panic?
>>>
>>>> Seems as of today that there is no tooling to support that check. Maybe 
>>>> it's not a widespread issue.
>>>
>>>
>>> As of today, the language also isn't changed :) Maybe someone who think 
>>> this is important enough to change the language, could also feel it's 
>>> important enough to write this tooling.
>>>
>>>>
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>>>
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