It is not.
Because the low items will be read if there are no highs available. If the low
isn’t read, the producer on the low will block.
Or you run out of memory if you cannot process the events fast enough - which
is also easily handled by bounding the queue - but then you may need to drop
items.
There are no free lunches.
But no deadlock.
> On Apr 29, 2021, at 9:26 AM, Ian Davis <m...@iandavis.com> wrote:
>
> On Thu, 29 Apr 2021, at 3:09 PM, robert engels wrote:
>> I will give you the pseudo code:
>>
>> { // step #1 do select on both
>> select high
>> select low
>> }
>>
>> if high read:
>> return high
>> else:
>> // we read a low so do a high poll
>> {
>> select high:
>> default:
>> }
>>
>> if high read:
>> enqueue low and return high
>> else:
>> if queue empty:
>> return low
>> else:
>> use queue and enqueue low from step #1 // FIFO order on low reads
>>
>> The above code will always return high values over low values (if high
>> available), and return low values in order of events
>
> This seems likely deadlock if the low channel is being filled continually by
> another goroutine. In addition I usually aim to give ownership of the channel
> to the writer so it can close cleanly, but mixing reads and writes in a
> single function greatly complicates that.
>
> Ian
>
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