Doesn’t that depend on what the uintptr refers to? Eg if it was allocated off 
heap to begin with then it should be stable  and computing a hash on it is 
valid. 

> On Jun 3, 2021, at 9:42 AM, 'Axel Wagner' via golang-nuts 
> <golang-nuts@googlegroups.com> wrote:
> 
> 
>> On Thu, Jun 3, 2021 at 4:19 PM christoph...@gmail.com 
>> <christophe.mees...@gmail.com> wrote:
> 
>> The documentation doesn’t specify that we can cast an uintptr into a uint64.
> 
> Both are integer types, so they can be converted. You might be worried about 
> their respective sizes and you are correct that the spec does not guarantee 
> that a uintptr is at most 64 bit. However, at least for any implementation I 
> know on any supported architecture, that's the case. If you *really* want to 
> make sure, you can do something like this:
> 
> func toBytes(v uintptr) []byte {
>     var out []byte
>     mask := ^uintptr(0)
>     for mask != 0 {
>         out = append(out, uint8(v))
>         v >>= 8
>         mask >>= 8
>     }
>     return out
> }
>  
> But really, you can just trust that a uintptr fits into a uint64. Or, if you 
> want to future-proof, assume it's uint64, but guard by build tags to known 
> architectures (so it at least fails to compile if that assumption ever 
> changes).
> 
>> To give some context, the application is for a cache with the hash key 
>> computed over a pointer to a heap allocated struct. I need to store the 
>> pointer in the cache entry to test for matching, but this would prevent the 
>> struct to be garbage collected. Storing the pointer as an uintptr would do 
>> the trick.
> 
> This is problematic. The address of a value can change, so the uintptr would 
> change as well. So there is no guarantee that your hash stays the same, in 
> subsequent calls.
> Today, that usually doesn't happen, but there is no guarantee it stays that 
> way. If you are willing to assume that it doesn't happen, you should 
> definitely also be willing to assume a uintptr fits into a uint64
>  
>> 
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