chmod 4755 is not enough. Your binary must be owned by root, to run root -
setuid means "run as owner".
Rich a következőt írta (2021. szeptember 20., hétfő, 19:54:33 UTC+2):
> Yes. I tried running an exec: cmd=exec.Command("whoami") and it came as my
> user id not root. But to set the permissions I'd run: 'chmod 4755
> myapplication'
>
> On Monday, September 20, 2021 at 11:20:39 AM UTC-4 Tamás Gulácsi wrote:
>
>> You mean "chown root app; chmod 4755 app" ?
>>
>> Rich a következőt írta (2021. szeptember 20., hétfő, 16:57:38 UTC+2):
>>
>>> I am trying to create a go program so that I can peform an action that
>>> is more complex than the example I have below. I can't give sudo right so
>>> run the application due to some policy we have at work that certain groups
>>> can only have read permissions. The company also have a policy that states
>>> any new directory / file is set with restrictive permissions. What I wanted
>>> to do is create a program that runs as root. (Like ping runs as root) but
>>> it doesn't seem to work.
>>>
>>> package main
>>>
>>> import (
>>> "fmt"
>>> "os"
>>> "os/exec"
>>> )
>>>
>>> func main() {
>>> cmd:=exec.Command("chmod","770", "/opt/app/mnt/mydirectory")
>>> cmd.Stdout = os.Stdout
>>> cmd.Stderr = os.Stderr
>>> err:=cmd.Run()
>>> if err != nil {
>>> fmt.Println("ERROR:", err)
>>> }
>>> }
>>>
>>> When I compile, then do a chmod 4755, and run it. I get a permissions
>>> denied. Looking for why this would be?
>>>
>>
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