Am developing a server (diameter) which will response with an AVP
SIP-Authenticate.
In the specification
" The SIP-Authenticate AVP is of type OctetString and It shall contain,
binary encoded, the concatenation of the authentication challenge RAND and
the token AUTN"
The RAND and the AUTN in this case are hexadecimal strings s1 and s2.
My problem is how to encode s1 and s2 concatenated and then be able to
decode at the server side too.
On Tue, Mar 14, 2023 at 9:13 AM Marcello H <marcel...@gmail.com> wrote:
> You can also use gob for that.
>
> Here are 2 functions from my library that can help.
>
> import "encoding/gob"
>
> /*
> encodeGob encodes a model to gob bytes.
> */
> func encodeGob(data any) ([]byte, error) {
> var (
> buf bytes.Buffer
> enc = gob.NewEncoder(&buf) // Will write to network.
> )
>
> err := enc.Encode(data)
>
> return buf.Bytes(), errors.Wrap(err, "encodeGob")
> }
>
> /*
> decodeGob decodes gob bytes to a model.
> */
> func decodeGob(decVal []byte, data any) (err error) {
> buf := bytes.NewBuffer(decVal)
> dec := gob.NewDecoder(buf)
> err = dec.Decode(data)
>
> return errors.Wrap(err, "decodeGob")
> }
>
> Op dinsdag 14 maart 2023 om 00:06:31 UTC+1 schreef robert engels:
>
>> Am arbitrary byte can be encoded in 2 HEX characters - only a 2x increase
>> in size not 8x.
>>
>> On Mar 13, 2023, at 2:35 PM, Volker Dobler <dr.volke...@gmail.com> wrote:
>>
>> On Monday, 13 March 2023 at 17:41:42 UTC+1 Van Fury wrote:
>>
>> Relating to my previous question, I have been reading but it is still not
>> clear to me what raw binary is, how is it different from
>> text formatted binary (fmt.Sprintf("%b", s1s2Byte))?
>>
>> "text formated binary" takes a stream of bytes and for each bit in
>> this stream output "0" or "1" as letters, i.e. the bytes 48==0x30
>> and 49==0x31. An eightfold blowup in size.
>> Try understanding how _text_ is encoded as bytes.
>>
>> Computers work on streams of bytes.
>> The meaning/interpretation of a single byte can vary:
>> Not all number can be stored in a single byte and
>> text has to be encoded by bytes too.
>> Please forget about "raw binary", there is no such thing.
>> String variables are a stream of bytes and do not need any encoding,
>> especially not something like "raw binary" that doesn't exist.
>> A stream of bytes can be _printed_ (encoded) as decimal, hexadecimal,
>> octal, base64 or even as bit ('0' and '1'). sometimes this is necessary
>> because the underlying protocol cannot transmit possible byte values.
>> When dealing with "binary" streams this cannot happen (it happens e.g.
>> when using JSON to transmit data).
>> You have to make clear what the output/encoding space should be
>> (and why!): There is a inconsistency between wanting "binary" and
>> a textual bit stream (which is not "binary" but text) and hexadecimal
>> encoding (also not binary but text).
>> You manoeuvred yourself in a corner by focusing on the solution
>> instead of the actual problem.
>>
>> V.
>>
>>
>> In my problem above I need to encode s1+s2 to raw binary before sending
>> the result to the server
>> which then decodes the raw binary back to s1+s2.
>>
>>
>>
>> On Mon, Mar 13, 2023 at 5:39 PM Van Fury <fury...@gmail.com> wrote:
>>
>> Do you mean encoding should be
>> rawdata := fmt.Print("%016d%s%s", len(s1), s1,s2)
>> or
>> rawdata := fmt.Printf("%016d%s%s", len(s1), s1,s2)
>>
>>
>>
>> On Monday, March 13, 2023 at 4:36:50 PM UTC+2 Alex Howarth wrote:
>>
>> You might be looking for strconv.ParseUint()
>> https://pkg.go.dev/strconv#ParseUint
>>
>> https://go.dev/play/p/qAO9LfLD41D
>>
>> On Mon, 13 Mar 2023 at 07:24, Van Fury <fury...@gmail.com> wrote:
>>
>>
>> Sorry I did not frame my question properly but what I would like to do is
>> to
>> encode concatenated s1 and s2 into raw binary and then decode the raw
>> binary
>> back to s1 and s2.
>>
>>
>> On Friday, March 10, 2023 at 11:36:09 PM UTC+2 Alex Howarth wrote:
>>
>> If s1 and s2 are a fixed length then you can just slice up the decoded
>> string based on the lengths. If they are of a variable length, you'll need
>> a separator in the input string to later split on when decoded (s3 := s1 +
>> ":" + s2 etc)?
>>
>> On Fri, 10 Mar 2023 at 10:33, Van Fury <fury...@gmail.com> wrote:
>>
>> Hi,
>>
>> I have two hexadecimal string values and would like to concatenate the
>> two strings and
>>
>> 1. encode the result to binary
>> 2. decode the resulting binary back to hexadecimal string
>>
>> I did the following but I was finding it difficult to decode the result
>> back. I ignore error check in this case.
>>
>> What i did so far:
>>
>> s1 := "1d28ed66824aa2593e1f2a4cf740343f"
>>
>> s2 := "dee2bd5dde763885944bc9d65419"
>>
>> s3 := s1 + s2
>>
>> s1s2Byte, _ := hex.DecodeString(s3)
>>
>> randAutnBin := fmt.Sprintf("%b", s1s2Byte)
>>
>> result:
>>
>> [11101 101000 11101101 1100110 10000010 1001010 10100010 1011001 111110
>> 11111 101010 1001100 11110111 1000000 110100 111111 11011110 11100010
>> 10111101 1011101 11011110 1110110 111000 10000101 10010100 1001011 11001001
>> 11010110 1010100 11001]
>>
>> I would like to decode the binary result back the hexadecimal string to
>> get s1 and s2.
>>
>> Any help?
>>
>> Van
>>
>> --
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