If you want to default GODEBUG=httpmuxgo121=0.
One way to do this is to set go1.22.0 on the go line of go.mod, or add a
//go:debug httpmuxgo121=0 to the go file of the main package.
On Monday, February 12, 2024 at 3:09:38 PM UTC+8 qiulaidongfeng wrote:
> Starting with go1.21, GODEBUG is set by default according to the go line
> of go.mod.
>
> On Monday, February 12, 2024 at 11:47:31 AM UTC+8 xab3r wrote:
>
>> Hello there
>>
>> I've just tried new routing patterns in Go 1.22.0, and I noticed that I
>> have to set httpmuxgo121=0 explicitly in order to get it enabled. When the
>> release notes say to "set httpmuxgo121=1 to restore the old behaviour". So,
>> as I understand it, by default, it should work with new path patterns.
>>
>> This is the handler
>> ```
>> mux.HandleFunc("GET /hello", func(w http.ResponseWriter, r *http.Request)
>> {
>> fmt.Fprint(w, "Hello")
>> })
>> ```
>>
>> So this piece of code is not gonna work if I run it like this
>> `$ go run main.go`
>> The server responds with 404.
>>
>> But it's working as expected when I explicitly set httpmuxgo121 to 0
>> `$ GODEBUG=httpmuxgo121=0 go run main.go`
>>
>> Also, I compiled go from sources with extra logs and `use121` variable
>> https://github.com/golang/go/blob/master/src/net/http/servemux121.go#L23
>> is set to 1 by default, when I don't specify it explicitly via the ENV
>> variable.
>>
>> What's the correct behaviour? Any clues are welcome
>>
>> Thanks
>>
>>
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