I am trying to get the following example to work but I keep getting the following error.
*java -cp googleapi.jar com.google.soap.search.GoogleAPIDemo mykey cached http://www.yahoo.com* Parameters: Client key = ABQIAAAA1x3Qiu3bqQlQI_3RdZC7HhT2yXp_ZAY8_ufC3CFXhHIE1NvwkxTg_7MpjBDqrWoaPE9wRuX4TfOzjA Directive = cached Args = http://www.yahoo.com Cached page: ============ The call to the Google Web APIs failed: com.google.soap.search.GoogleSearchFault: [SOAPException: faultCode=SOAP-ENV:Protocol; msg=Unsupported response content type "text/html; charset=UTF-8", must be: "text/xml". Response was: <html><head> <meta http-equiv="content-type" content="text/html;charset=utf-8"> <title>404 Not Found</title> <style><!-- body {font-family: arial,sans-serif} div.nav {margin-top: 1ex} div.nav A {font-size: 10pt; font-family: arial,sans-serif} span.nav {font-size: 10pt; font-family: arial,sans-serif; font-weight: bold} div.nav A,span.big {font-size: 12pt; color: #0000cc} div.nav A {font-size: 10pt; color: black} A.l:link {color: #6f6f6f} A.u:link {color: green} //--></style> <script><!-- var rc=404; //--> </script> </head> <body text=#000000 bgcolor=#ffffff> <table border=0 cellpadding=2 cellspacing=0 width=100%><tr><td rowspan=3 width=1% nowrap> <b><font face=times color=#0039b6 size=10>G</font><font face=times color=#c41200 size=10>o</font><font face=times color=#f3c518 size=10>o</font><font face=times color=#0039b6 size=10>g</font><font face=times color=#30a72f size=10>l</font><font face=times color=#c41200 size=10>e</font> </b> <td> </td></tr> <tr><td bgcolor="#3366cc"><font face=arial,sans-serif color="#ffffff"><b>Error</b></td></tr> <tr><td> </td></tr></table> <blockquote> <H1>Not Found</H1> The requested URL <code>/search/beta2</code> was not found on this server. <p> </blockquote> <table width=100% cellpadding=0 cellspacing=0><tr><td bgcolor="#3366cc"><img alt="" width=1 height=4></td></tr></table> </body></html> ] *Can someone help me out with this?* *Also does anyone have a working example of a java application using the google ajax based search?* * Do I have to have a key in order for this to work? I was not clear on that.* I have tried the following with no luck as well. import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.net.MalformedURLException; import java.net.URL; import java.net.URLConnection; import org.json.*; public class SearchTestGoogle { /** * @param args * @throws JSONException * @throws IOException */ public static void main(String[] args) throws JSONException, IOException { // TODO Auto-generated method stub // This example request includes an optional API key which you will need to // remove or replace with your own key. // Read more about why it's useful to have an API key. // The request also includes the userip parameter which provides the end // user's IP address. Doing so will help distinguish this legitimate // server-side traffic from traffic which doesn't come from an end-user. // + "q=Paris%20Hilton&key=CSIZCKFQFHLdm6TJhHUGIJBYZEA08ZGQ&userip=192.168.1.104"); URL url = new URL( "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&"; + "q=http://www.yahoo.com&userip=192.168.1.104";); URLConnection connection = url.openConnection(); connection.addRequestProperty("Referer", "http://www.yahoo.com";); String line; StringBuilder builder = new StringBuilder(); BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream())); while((line = reader.readLine()) != null) { builder.append(line); } JSONObject json = new JSONObject(builder.toString()); System.out.println(json.toString()); // now have some fun with the results... } } -- You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-ajax-search-api?hl=en.
