Blogborg is correct. Your link href's should not be pointing to the RESTful API endpoints but to your own PHP. Send a parameter, whether start or page, etc., which can be translated into the start parameter that the RESTful API needs to return the next page of results and then parse them just as you did the first page.
Jeremy R. Geerdes Effective website design & development Des Moines, IA For more information or a project quote: http://jgeerdes.home.mchsi.com [email protected] If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan Church! On Mar 29, 2010, at 10:01 AM, [email protected] wrote: > Hi Saravanan, > > Wouldn't it be much easier to have each HREF link to your PHP script, > pass the start variable and then call the Google API straight from > PHP? > > <A HREF="mypagingscript.php?start=32" TARGET="_SELF">Go to 32nd result > and onwards</A> > > And then in your PHP script: > > is_numeric($_GET['start'])?$start=$_GET['start']:$start=0; > $url = "http://ajax.googleapis.com/.../?v=1.0&q=";. > $_SESSION['searchtext']."&start=".$start."..." > > $retray = json_decode(include($url)); > > That would save you a lot of mixing clientside, serverside, JS and so > on... > > Good luck, > > Ruben (Blogborg) > > >> v=1.0&q=" >> >> .$searchQuery."&start=".$pg->start."&rsz=large&key=ABQIAAAAPJbd6fVsvq3XRmiloFh50RToOL0JAC4cb7rJK5CdsUkjTh5NqBRYQKUCoDmCuE6fep07WNQcFQbjPQ&userip=203.193.157.39"; > > > > > > On Mar 29, 9:30 am, saravanan <[email protected]> wrote: >> Hi, >> >> Now that i have setup everything, i am facing a problem of how to >> traverse through the results page, by clicking on the links at the >> bottom of the page. >> >> I am using the following code for the links to further search pages at >> the bottom of this search page. >> [code] >> <a href="javascript: callSubmit('<? >> echo $url = "http://ajax.googleapis.com/ajax/services/search/web? >> v=1.0&q=" >> >> .$searchQuery."&start=".$pg->start."&rsz=large&key=ABQIAAAAPJbd6fVsvq3XRmiloFh50RToOL0JAC4cb7rJK5CdsUkjTh5NqBRYQKUCoDmCuE6fep07WNQcFQbjPQ&userip=203.193.157.39"; >> >> ?> '); " onclick="javascript: callSubmit('<? >> echo $url = "http://ajax.googleapis.com/ajax/services/search/web? >> v=1.0&q=" >> >> .$searchQuery."&start=".$pg->start."&rsz=large&key=ABQIAAAAPJbd6fVsvq3XRmiloFh50RToOL0JAC4cb7rJK5CdsUkjTh5NqBRYQKUCoDmCuE6fep07WNQcFQbjPQ&userip=203.193.157.39"; >> >> ?> '); target="_self"> >> [/code] >> In the callSubmit function in javascript, i have used as >> >> <script language="javascript" type="text/javascript"> >> function callSubmit(newUrl) >> { >> document.getElementById("newQuery").value=newUrl; >> alert(document.getElementById("newQuery").value); >> document.searchForm.submit(); >> } >> </script> >> >> I am able to get the URL in the alert() window. But the form is not >> submitted, and the javascript error reported is : Object does not >> support this property or method. >> >> Please help me on this issue. >> >> regards, >> >> saravanan >> >> On Mar 25, 3:26 pm, Jeremy Geerdes <[email protected]> wrote: >> >>> The &start= is to be appended to thehttp://ajax.googleapis.comurlwhich you >>> call from within your own application to get subsequent pages. The >>> moreResultsUrl is simply to direct your users to where they can run a more >>> comprehensive search on Google itself. I do not know what the parameters >>> you asked about in that url are; you will never need to worry about them. >> >>> Jeremy R. Geerdes >>> Effective website design & development >>> Des Moines, IA >> >>> For more information or a project quote:http://jgeerdes.home.mchsi.com >>> [email protected] >> >>> If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan >>> Church! >> >>> On Mar 25, 2010, at 1:45 AM,saravananwrote: >> >>>> Hi, >> >>>> Thank you very much for your reply. I have one another small query to >>>> be clarified by you. >>>> In the bottom of the page, we give the links as 1 2....n. >> >>>> You have suggested appending of the &start to the url of the query. >>>> Shall i use the url as "http://www.google.co.in/search? >>>> hl=en&rsz=large&q=i+need+an+apple&start=".$pg->start" or have i got to >>>> use the initial url like "http://ajax.googleapis.com/ajax/services/ >>>> search/web?v.....". >>>> where the $pg-> start is getting the value of the start property from >>>> the object $json->responseData->cursor->pages. >> >>>> Please suggest me. >> >>>> Further, google search url is like this "http://www.google.co.in/ >>>> search?hl=en&rlz=1C1DVCC_enIN361IN361&q=i+need+an >>>> +apple&start=20&sa=N". Can you tell me the meaning of the "rlz" and >>>> &sa=N in the above URL. This for my knowledge only. >> >>>> Thank you.. >> >>>> On Mar 24, 9:29 pm, Jeremy Geerdes <[email protected]> wrote: >>>>> Two things. First, add &rsz=large to your url. This will tell the API to >>>>> return 8 results at a time instead of 4. And second, rather than looking >>>>> at the $json->responseData->cursor->moreResultsUrl, check out the >>>>> $json->responseData->cursor->pages array. This will contain an array of >>>>> the pages you can get. Each element in the array will have a start >>>>> property which you can use to build a new url for the RESTful API. Simply >>>>> add &start=[one of these start properties] to get additional sets of >>>>> results. Once you've exhausted all the pages you can get from the pages >>>>> array, then you can direct users to the moreResultsUrl. >> >>>>> Hope that makes sense! >> >>>>> Jeremy R. Geerdes >>>>> Effective website design & development >>>>> Des Moines, IA >> >>>>> For more information or a project quote:http://jgeerdes.home.mchsi.com >>>>> [email protected] >> >>>>> If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan >>>>> Church! >> >>>>> On Mar 24, 2010, at 2:35 AM,saravananwrote: >> >>>>>> Hi, >> >>>>>> I have currently used the following search query: i+need+an+apple. >> >>>>>> In my test site, i am using the JSON alongwith PHP to parse the search >>>>>> results returned from Google and display them as per my need. >> >>>>>> The problem that i face currently is that I get only top 4 results and >>>>>> get 8 page references in cursor object. I did get only one url for >>>>>> more results in "moreResultsUrl" >> >>>>>> I want my page to be analogous to the google search page. I need more >>>>>> results and also when i click on the next links in that page, it >>>>>> should go to the next search result page. >> >>>>>> The code i am using is as follows, This code is in PHP. >> >>>>>> [code] >>>>>> $ct = 0; >>>>>> foreach( $json->responseData->results as $res) >>>>>> { >>>>>> ?> >>>>>> <h4> <a href=" <? echo $res->url ?>" target ="_blank" > <? >>>>>> echo ($res->title); ?> </a></h4> <? echo "<br />"; >>>>>> echo $res->content."<br />"; >>>>>> ?> <a href=" <? echo $res->url ?>" target ="_blank" >>>>>> style="color:Green" > <? >>>>>> echo ($res->url); ?> </a> <? echo "<br />"; >>>>>> echo "Cached URL: ".$res->cacheUrl."<br />"; >>>>>> } >> >>>>>> echo "<br /><br />"; >> >>>>>> foreach($json->responseData->cursor->pages as $pg) >>>>>> { >>>>>> ?> <a href=" <? echo $json->responseData->cursor->moreResultsUrl;?>" >>>>>> target="_blank" > >>>>>> <? echo $pg->label; >>>>>> ?> </a> >>>>>> <? >>>>>> } >>>>>> [/code] >> >>>>>> Anybody please help me in getting all links in the current page and >>>>>> also tell me ways to get the link url to other search pages as like >>>>>> those in google's page. >> >>>>>> Thanks, >> >>>>>> saravanan >> >>>>>> -- >>>>>> You received this message because you are subscribed to the Google >>>>>> Groups "Google AJAX APIs" group. >>>>>> To post to this group, send email to >>>>>> [email protected]. >>>>>> To unsubscribe from this group, send email to >>>>>> [email protected]. >>>>>> For more options, visit this group >>>>>> athttp://groups.google.com/group/google-ajax-search-api?hl=en. >> >>>> -- >>>> You received this message because you are subscribed to the Google Groups >>>> "Google AJAX APIs" group. >>>> To post to this group, send email to >>>> [email protected]. >>>> To unsubscribe from this group, send email to >>>> [email protected]. >>>> For more options, visit this group >>>> athttp://groups.google.com/group/google-ajax-search-api?hl=en. > > -- > You received this message because you are subscribed to the Google Groups > "Google AJAX APIs" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/google-ajax-search-api?hl=en. > -- You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. 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