Thanks Jeremy. Sorry for posting code here. Thanks for the help its Working Now. Bj
On May 25, 6:50 pm, Jeremy Geerdes <[email protected]> wrote: > Rather than posting code into the group (which is notorious for messing up > formatting and such), a link to your page would be best. Just looking at > your code, I'm thinking that there is a lot more complexity here than there > needs to be. Beyond that, I'm thinking that the code is not triggering as you > think it should be. Namely, you're calling $.Load with the settings of each > feed, in succession, and resetting the onload callback each time. It would be > far better if you call google.setOnLoadCallback once, to a function that will > get your li elements and their values and, for each one, call a common > function with the appropriate settings. Something more like this: > > (function(){ > function init(){ > $('#divRSSLinks li label').each(function(index, value){ > loadFeed({ > url : $(this).text(), > divId : 'feed', > noOfFeed : 4 > }); > }); > } > > function loadFeed(opt_options){ > var feed = new google.feeds.Feed(opt_options.url); > feed.setNumEntries(opt_options.noOfFeed); > feed.load(function(result){ > if(!result.error){ > var feeddiv = $('#' + opt_options.divId), > li = '<li>' + result.feed.link + '</li>', > divOne = ''; > $('#vtab ul').append(li); > for(var i=0; i<result.feed.entries.length; i++){ > var entry = result.feed.entries[i]; > divOne += '<a href="' + entry.link + '" target="_blank">' + > entry.title + '</a><br />'; > } > $('#vtab').append('<div class="rssContent">' + divOne + '</div>'); > } > }); > } > > google.setOnLoadCallback(init); > > })() > > You'll have to be on the lookout for syntax errors from wrapped lines. And I > haven't tried to run it at all to make sure that it works beyond that. But it > should be close. > > Jeremy R. Geerdes > Generally Cool Guy > Des Moines, IA > > For more information or a project quote: > [email protected] > > If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan > Church! > > On May 25, 2012, at 12:41 AM, simplybj wrote: > > > > > > > > > Here is the code. > > First I am using > > <script type="text/javascript"> > > google.load("feeds", "1"); > > </script> > > > js to load feed is as: > > (function($) > > { > > $.Load = function(settings) > > { > > Options = $.extend({ url: '', divID: '', noOfFeed: 4 }, > > settings); > > var Rss = { > > initialize: function() > > { > > var feed = new google.feeds.Feed(Options.url); > > feed.setNumEntries(Options.noOfFeed); > > var li = ''; > > var divOne = ''; > > var div = ''; > > feed.load(function(result) > > { > > if (!result.error) { > > var feeddivid = $('#' + Options.divID); > > li += '<li>' + result.feed.link + '</li>'; > > for (var i = 0; i < > > result.feed.entries.length; i++) { > > var entry = result.feed.entries[i]; > > divOne += '<a href="' + entry.link + '" > > target="_blank">' + entry.title + ' </a><br />'; > > } > > } > > $('#vtab ul').append(li); > > div += '<div class="rssContent">' + divOne + '</ > > div>'; > > $('#vtab').append(div); > > > }); > > }, > > GoogleRss: function() > > { > > google.setOnLoadCallback(Rss.initialize); > > }, > > init: function() > > { > > Rss.GoogleRss(); > > } > > }; > > Rss.init(); > > }; > > $.fn.GoogleLoadRss = function(Settings) > > { > > $.Load(Settings) > > } > > } (jQuery)); > > > I am calling this js from another js file Passing dynamic link: > > > $('#divRSSLinks li label').each(function(index, value) > > { > > var text = $(this).text(); > > $.Load({ url: text, divID: 'feed', noOfFeed: 4 }); > > }); > > All i get is the feed from last link repeted over number of links. > > Did this help you to figure out the problem? > > On May 25, 9:37 am, Jeremy Geerdes <[email protected]> wrote: > >> Without being able to see your complete code, it's tough to say what's > >> going on here. However, I think that what is probably happening is that > >> you are rapidly creating a large number of Feed objects and assigning them > >> each, in turn, to feed. You are then loading only the last one (feed.load > >> is not in your loop). To get a more exact answer, you'll need to provide a > >> link to your page, working or not. > > >> Jeremy R. Geerdes > >> Generally Cool Guy > >> Des Moines, IA > > >> For more information or a project quote: > >> [email protected] > > >> If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan > >> Church! > > >> On May 24, 2012, at 11:17 PM, simplybj wrote: > > >>>http://stackoverflow.com/questions/10736784/multiple-feed-in-one-webs... > > >>> I am using Google feed API to load rss in my website. > >>> The Procedure mentioned inhttps://developers.google.com/feed/v1/devguide > >>> Works Well for fetching rss from a link. > >>> var feed = new google.feeds.Feed("http://stackoverflow.com/feeds";); > >>> //other Codes > >>> google.setOnLoadCallback(myFunction); > > >>> My scenario is to load multiple rss feed in my website for Dynamic > >>> Links > >>> For example at an instance if links are as follows: > > >>>http://www.codeplex.com/site/feeds/rss > >>>http://stackoverflow.com/feeds > >>>http://fastpshb.appspot.com/feed/1/fastpshb/rss > >>> and i tried to fetch Rss for multiple dynamic link. > > >>> $('li').each(function(index, value) > >>> { > >>> var text = $(this).text(); > >>> var feed = new google.feeds.Feed(text); > >>> }); > >>> //Other Codes > >>> google.setOnLoadCallback(myFunction); > > >>> Only the Last Link's rss is get fetched. > > >>> On this linkhttps://developers.google.com/feed/v1/reference#resultFind > >>> it is mentioned that > >>> .setOnLoadCallback(callback) is a static function that registers the > >>> specified handler function to be called once the page containing this > >>> call loads, where callback is a required function called when the > >>> containing document is loaded and the API is ready for use (e.g., > >>> after onLoad). > > >>> Is that the reason .setOnLoadCallback execute the last link? > >>> What is the solution to this problem? > > >>> -- > >>> You received this message because you are subscribed to the Google > >>> Groups "Google AJAX APIs" group. > >>> To post to this group, send email to > >>> [email protected] > >>> To unsubscribe from this group, send email to > >>> [email protected] > >>> To view this message on the web, visit > >>>http://groups.google.com/group/google-ajax-search-api?hl=en_US > >>> For more options, visit this group at > >>>http://groups.google.com/group/google-ajax-search-api?hl=en?hl=en > > > -- > > You received this message because you are subscribed to the Google > > Groups "Google AJAX APIs" group. > > To post to this group, send email to > > [email protected] > > To unsubscribe from this group, send email to > > [email protected] > > To view this message on the web, visit > >http://groups.google.com/group/google-ajax-search-api?hl=en_US > > For more options, visit this group at > >http://groups.google.com/group/google-ajax-search-api?hl=en?hl=en -- You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. 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