Just took a look at DataNucleus documentation - Timestamp cannot be used as a type of a field -
http://www.datanucleus.org/products/accessplatform_1_1/jpa/types.html On Nov 13, 4:47 pm, m seleron <seler...@gmail.com> wrote: > Hi > If it is unquestionable even if the Nano second is lost > I think that I can do normal registration by using "java.util.Date". > > thanks. > > On 11月13日, 午後7:13,Zaske<yair.zaslav...@gmail.com> wrote: > > > Hi all, > > I have a problem with using JPA & Google App engine > > > Here is my entity: > > > @Entity > > public class UserEntity { > > > public String getUserName() { > > return userName; > > } > > > public void setUserName(String userName) { > > this.userName = userName; > > } > > > public Timestamp getTimestamp() { > > return timestamp; > > } > > > public void setTimestamp(Timestamp timestamp) { > > this.timestamp = timestamp; > > } > > > private String userName; > > private Timestamp timestamp; > > /** > > * > > */ > > public UserEntity() { > > // TODO Auto-generated constructor stub > > } > > > public void setID(Long iD) { > > ID = iD; > > } > > > �...@id > > �...@generatedvalue(strategy = GenerationType.IDENTITY) > > public Long getID() { > > return ID; > > } > > > private Long ID; > > > } > > > I then perform inside the code: > > > UserEntity entity = new UserEntity(); > > entity.setTimestamp(new > > Timestamp(System.currentTimeMillis > > ())); > > entity.setUserName(user.getNickname()); > > > try > > { > > em.getTransaction().begin(); > > em.persist(entity); > > em.getTransaction().commit(); > > > } > > catch (Exception ex) > > { > > String msg = "Error in persisting user"; > > log.severe(msg); > > writer.print(msg); > > ex.printStackTrace(); > > return; > > } > > finally > > { > > if (em.getTransaction().isActive()) > > { > > em.getTransaction().rollback(); > > } > > > } > > > And in order to select the entities , I did: > > > StringBuilder sb = new StringBuilder(); > > sb.append("select u from "); > > sb.append(UserEntity.class.getSimpleName()); > > sb.append(" u "); > > Query q = em.createQuery(sb.toString()); > > q.setMaxResults(5); > > List<UserEntity> alreadyLoggedInUsers = > > (List<UserEntity>) > > q.getResultList(); > > > Turns out that java.sql.Timestamp is not a supported type, in contrast > > to JPA with hibernate implementation (I'm using JBoss 3.2.1 GA as J2EE > > server, and I can persist entities with timestamps) > > What are the supported types? > > -- You received this message because you are subscribed to the Google Groups "Google App Engine for Java" group. To post to this group, send email to google-appengine-j...@googlegroups.com. To unsubscribe from this group, send email to google-appengine-java+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/google-appengine-java?hl=.
