This seems to work for displaying a live Picasa web albums on my
page:
def renderhtml(request):
req=urlfetch.fetch('http://www.picasaweb.google.com')
response= HttpResponse()
response.write(req.content)
return response
Thank you Alexander!
On Sep 20, 9:32 pm, Alexander Kojevnikov <[EMAIL PROTECTED]>
wrote:
> I just tried this inhttp://shell.appspot.com/:
>
> >>> from google.appengine.api import urlfetch
> >>> r = urlfetch.fetch('http://www.muspy.com')
> >>> print r.content
>
> <?xml version="1.0" encoding="utf-8"?>
> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
> "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
> ....
> ....
>
> As you can see, no headers are present in the content. Which URL are
> you fetching?
>
> On Sep 21, 9:43 am, uo <[EMAIL PROTECTED]> wrote:
>
> > how can i remove the status info ie
>
> > Status: 200 OK
> > Last-Modified: Sat, 20 Sep 2008 03:47:52 GMT
> > ETag: e608d454f548741614b550558645b689
> > Content-Type: text/html; charset=utf-8
> > Expires: Sat, 20 Sep 2008 03:47:51 GMT
> > Cache-Control: max-age=0
>
> > <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
> > <html><head>
>
> > from my response object after doing a
> > urlfetch.fetch(url).content ???????
> > pliz help..anyone
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