Ah, never mind. I see how it works. Simple: add handler to app.yaml.
Will give it a go.

Cheers,
Jason

On Oct 6, 4:16 pm, "[EMAIL PROTECTED]"
<[EMAIL PROTECTED]> wrote:
> Thanks a lot for the advice. Still quite a novice, so can you tell me
> more about how to implement the function? Not entirely sure where to
> stash the code (function in main.py w/ all the rest of my code) or how
> to call it with webcron (which sounds like exactly what I need).
>
> On Oct 6, 3:56 pm, "David Symonds" <[EMAIL PROTECTED]> wrote:
>
> > On Mon, Oct 6, 2008 at 6:12 PM, [EMAIL PROTECTED]
>
> > <[EMAIL PROTECTED]> wrote:
> > > What's the best means of cleaning lingerers these up? Entity has a
> > > datetime.datetime field (called creation).
>
> > > Will code this simple suffice:
>
> > > def cleanDB():
> > >    """Clean out entities older than two hours."""
> > >    results = PalettesDB.all()
> > >    for result in results:
> > >        age = datetime.datetime.now() - result.creation
> > >        if age.seconds > 7200:
> > >            db.delete(result)
>
> > > How can I call it in a cron job fashion? (It doesn't necessarily need
> > > to run with ever user's visit.)
>
> > You'd be better with code like:
>
> > def cleanDb():
> >   cutoff = datetime.datetime.now() - datetime.timedelta(hours=2)
> >   for result in PalettesDB.all().filter('creation <', 
> > cutoff).order('creation')
> >     result.delete()
>
> > That's much simpler, shifts the filtering burden to the datastore's
> > index (and thus much faster), and prevents any session from lingering
> > indefinitely.
>
> > You can just hook that up to a very simple handler, and ping it every
> > hour or so via something like webcron.
>
> > Dave.
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