> On Oct 25, 2:49 am, yejun wrote:
>> Actually, you still need to supply a empty dict object
>> anykind = type("KindName", (db.Expando,), dict())
>>
>> obj1 = anykind()
>> obj1.put()
>>
>> Here "anykind" is just a variable name, it is not necessary to match
>> KindName, but KindName is the name used for datastore.hey, interesting stuff here. couple of questions: 1. is there a way to retrieve a list of kinds used by an app, or we need to keep track of them? 2. i have a case where about 300 users have entity collections from various "models". these collections vary in size from 10 to 10 thousand records, depending on the user. i don't need to fetch data from all users at any point. so, from a performance perspective, is it better to give each user its own kind (say "user1_kindname", "user2_kindname" etc), and fetch directly from them depending on the user, or it doesn't matter and i can just use a single kind for each model, plus a reference property to the user? hope this makes sense. :-) thanks, -- rodrigo --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google App Engine" group. To post to this group, send email to google-appengine@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/google-appengine?hl=en -~----------~----~----~----~------~----~------~--~---
