The next function is a bit faster import re def formatAsDollars(amount): part = ("%.2f"%amount).split(".") part[0] = re.sub(r'\B(?=(...)*$)',',',part[0]) return '$'+'.'.join(part)
2008/12/24 Joel Odom <joelo...@gmail.com>: > Here's a little function I wrote that you may have: > > def formatAsDollars(amount): > dollars = int(amount) > cents = amount - dollars > > i = 0 > reverseDollarPlaces = [] > for p in str(dollars)[::-1]: > if i % 3 == 0 and i: > reverseDollarPlaces.append(',') > reverseDollarPlaces.append(p) > i += 1 > > return '$%s.%.2i' % (''.join(reverseDollarPlaces[::-1]), int(100*cents)) > On Tue, Dec 23, 2008 at 2:32 PM, Shay Ben Dov <shay.ben...@gmail.com> wrote: >> >> Hi, >> >> I know that if >> >> sum = 560000.0 >> >> then >> >> {{ sum|floatformat:2 }} will display 560000.00 >> >> How we get $560,000.00 >> >> Thanks, >> >> Shay Ben Dov > -- > http://giscoder.blogspot.com/ --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google App Engine" group. To post to this group, send email to google-appengine@googlegroups.com To unsubscribe from this group, send email to google-appengine+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/google-appengine?hl=en -~----------~----~----~----~------~----~------~--~---