Cheers Guys,
I went the simplejson route, I was wondering is there much difference
performance wise in the way you've removed the jsonp text, I've done
it this way:
...
data = urlfetch.fetch(url, headers={},
payload=params,method=urlfetch.POST)
json = re.search ('{.*}', data.content )
obj = simplejson.loads(json.group(0), 'iso8859-1')
...
Cheers again. =0)
On 23 Aug, 13:18, Anthoni <anthoni.gard...@gmail.com> wrote:
> Hi veearrsix,
>
> Like vp mentioned above, the fastest way to query flickr is to use
> their json api,
> Below is some code that I use in one of my Google Wave Robots to do
> such a thing, hope it helps.
> The code was given in the Robots group and is not mine, but it does
> work.
>
> [code]
> def searchFlickr(query):
> results = []
> url = 'http://api.flickr.com/services/rest/?
> method=flickr.photos.search&api_key=13b98c74bedac9150a428e87bc782e81&format=json&per_page=5&text=
> %s' % (urllib.quote(query))
> content = urlfetch.fetch(url=url).content
> content =content[:-1].replace("jsonFlickrApi(","")
> for item in simplejson.loads(content)['photos']['photo']:
> results.append('http://farm'+str(item['farm'])
> +'.static.flickr.com/'+str(item['server'])+'/'+str(item['id'])+'_'+str
> (item['secret'])+'_m.jpg')
>
> return results
> [/code]
>
> Note, you will need a simplejson, urlfetch and urllib imports in order
> for it to work.
>
> Regards
> Anthoni
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