I get the same error, and I'm just outputting text, no logging. I
hope this limitation gets removed. Let me know if anyone knows a
workaround besides using another cron service.
On Nov 25, 4:28 am, googlegeeza
<gwynhow...@steppingstonesoftware.co.uk> wrote:
> yes, app.yaml is correctly configured - i can run the code via a url
>
> On Nov 24, 2:36 am, Eli Jones <eli.jo...@gmail.com> wrote:
>
>
>
> > does your app.yaml have the appropriate lines to handle the cron url as
> > well?
>
> > app.yaml should have this line before other handlers:
> > - url: /testcron
> > script: test.py
> > or something like that..
>
> > On Mon, Nov 23, 2009 at 8:43 AM, googlegeeza <
>
> > gwynhow...@steppingstonesoftware.co.uk> wrote:
> > > i know this has been posted before, but in other posts the error was
> > > caused by redirects and other issues.
>
> > > i have a cron job scheduled to run every minute (also tried it every 5
> > > minutes). the cron job runs some code which prints a string to the the
> > > log, that's it. but it doesn't run. the error on the cron jobs page in
> > > the admin console is "Too many continues". This doesn't make sense as
> > > I am not doing anything in the job, just printing to the log. Code as
> > > below:
>
> > > cron.yaml:
> > > cron:
> > > - description: TestCron
> > > url: /testcron
> > > schedule: every 1 minutes
>
> > > test.py:
> > > class TestCron(webapp.RequestHandler):
> > > def get(self):
> > > logging.info('cron test')
>
> > > application = webapp.WSGIApplication( [('/testcron', TestCron),],
> > > debug=True)
>
> > > Why is it reporting too many continues? I am not looping anything, or
> > > causing anything to 'continue' in any way.
>
> > > Nothing gets printed to the log which suggests it's not even trying to
> > > run my TestCron class.
>
> > > Thanks in advance ...
>
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