This should also work:

list(set(a) & set(b) & set(c))

You can get the intersection of tags with &.

Best Regards,

Jesaja Everling

On Fri, Jan 29, 2010 at 1:26 AM, johnP <j...@thinkwave.com> wrote:
> One possibility:
>
>>>> a,b,c,= [1,2,3,4,5], [4,5,6,7,8], [4,5,99,88,77]
>>>> res = list(set([i for i in (a+b+c) if (a+b+c).count(i) >1]))
>>>> print res
> [4, 5]
>
> johnP
>
> On Jan 28, 2:48 pm, Robert Kluin <robert.kl...@gmail.com> wrote:
>> You might want to look at the "set" type in the standard library.
>>
>> Robert
>>
>>
>>
>> On Thu, Jan 28, 2010 at 2:41 PM, Adam <adam.crossl...@gmail.com> wrote:
>> > You might want to ask this over on comp.lang.python, as this is a
>> > Python-specific question. It is not really related to AppEngine.
>>
>> > On Jan 28, 2:28 pm, alf <alberto....@gmail.com> wrote:
>> >> I forgotted to say.
>>
>> >> in more than 2 list.
>>
>> >> thanks
>>
>> >> On Jan 28, 8:03 pm, alf <alberto....@gmail.com> wrote:
>>
>> >> > we have two arrays
>>
>> >> > a=[a,b,c,d,e]
>>
>> >> > b=[x,c,e,w]
>>
>> >> > I would like get a arry with only common value ej.
>>
>> >> > res=[c,e]
>>
>> >> > how can do it
>>
>> >> > many tanks
>>
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