Any reply from google guys??
Hi,
I have 2-3 properties(Unowned Relationship keys) in my class which i
will be
using in where clause to filter records.
Class PropertyAd{
....
Key locationKey; //This will point for which location this ad has been
created
Key categoryKey;//This will point for which category this ad has been
created.
List<Key> featuresKey;//It will tell what fatures this property have
e.g.
Fully Furnished,With Parking etc, as i dont know what kind of feature
it can
have in future so i am creating all the features in seprate table/
class and
refernecing from here. Say i could have max 50 features.
}
Now i can query like this
1) Select PropertyAd where locationKey=SomeKey
2) Select PropertyAd where locationKey=SomeKey and
categoryKey=SomeOtherkey
3) Select PropertyAd where locationKey=SomeKey and
categoryKey=SomeOtherkey
and featureKey = someFeatureKey1 and featureKey = someFeatureKey2
Now for query 1 i don't need to create explicit index
for query 2 , 1 index will be created
e.g. if LocationKey is Location(2) and CategoryKey is Category(3)
then 1 index entry will be created Location(2) +Category(3) (or may be
Category(3) + Location(2) too but not sure)
for query 3 i am not sure how index will be created
if for one propertyAd i have LocationKey is Location(2) and
CategoryKey is
Category(3) featureKey Feature(10) and featureKey(12)
then will it indexes as all combination of all four keys which will be
4*3*2*1=24 indexes(is it true?)
Now i am thinking keys take care of most of the things then why not i
put my
all unowned foreign reference in one List as
Class PropertyAd{
....
List<Key> allKey;//It will have Location key, CategoryKey, feature key
or
any other key in future as per new requirment
}
and my queries will be like this
1) Select PropertyAd where allKey=SomeKey
2) Select PropertyAd where allKey=SomeKey and allKey=SomeOtherkey
3) Select PropertyAd where allKey=SomeKey andallKey =SomeOtherkey and
allKey= someFeatureKey1 and allKey= someFeatureKey2
So if for one property ad i have four keys in this list will it create
4*3*2*1 indexes or it will just create 4 indexes.
I am not sure how the indexes will be created and how much for it
looks like
second solution will be much better.
All comments/suggestions are welcome
Thanks in advance
Ravi.
On Feb 3, 5:25 pm, Ravi <ping2r...@gmail.com> wrote:
> Still not clear how the indexes will look like...
> any google guy?
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