To improve my previous post: no need to use list(). You can do
sorted(set(tweetlist)).

On Mon, Nov 14, 2011 at 2:29 PM, Matt Jibson <matt.jib...@gmail.com> wrote:
> From http://docs.python.org/library/stdtypes.html#set-types-set-frozenset:
> "A set object is an unordered collection"
>
> You can use set() to filter out duplicates. But then you need to
> convert back to a list to be able to sort:
> result = sorted(list(set(tweetlist)))
>
> On Mon, Nov 14, 2011 at 2:22 PM, pdknsk <pdk...@googlemail.com> wrote:
>> http://shell.appspot.com/
>>
>>>>> set([1,2,3,4,5,1,2])
>> set([1, 2, 3, 4, 5])
>>
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