and how to deal with the method renderJson() in Result and Search class ? or parse the q ? Thanks everyone : ) please help me
2012/8/17 forNightmare TF <callfatman...@gmail.com> > everyone : ) I have A database that can search like " > http://key.xxxxxx.org:10093/?q="; when type the keyword in url (behind the > =mark), it can show lots of json data. > > Now i write a simple webapp on GAE use webapp2 : on the /search page, when > i type the keyword, it can parse the jsondata content on the /result page. > Here is my part of code : > > def renderJson(): > > conn = httplib.HTTPConnection('key.eagle-project.org:10093') > > conn.request('GET', '/%E7%A0%B4%E7%A2%8E%E6%9C%BA') > > res = conn.getresponse() > > data = res.read() > > j = json.loads(data) > > return j['data']['group'][0]['resultitem'][0]['word'] > > class BaseHandler(webapp2.RequestHandler): > > def render(self, template, **kw): > > self.response.out.write(render_str(template, **kw)) > > def write(self, *a, **kw): > > self.response.out.write(*a, **kw) > > > class Result(BaseHandler): > > def get(self): > > #q = self.request.get > > self.render('result.html', result = renderJson()) > > app = webapp2.WSGIApplication([ > > ('/search', Search), > > ('/result', Result) > > ], > > debug=True) > > How can i parse the params in url and render the content out the result > page, the templates that i parse the {{result}}，and how parse the search > 'q' into the conn.quest ? > -- You received this message because you are subscribed to the Google Groups "Google App Engine" group. To post to this group, send email to google-appengine@googlegroups.com. To unsubscribe from this group, send email to google-appengine+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/google-appengine?hl=en.
