In C++ you can use string streams, you should include <sstream>
/* You can use an actual string or char* as a parameter, not completely sure
if it is iss = "2 3" or iss("2 3") */
istringstream iss = "2 3 4";
int x;
while ( iss >> x ) {
printf("%d\n", x);
}
Output would be:
2
3
4
in plain C you could do something like this, there are probably better ways.
char* ptr = "2 3 4"; /* again use actual line here */
while ( *ptr != 0 ) {
while ( *ptr != 0 && !isdigit(*ptr) ) ++ptr;
/* this line is needed if the line may not end in a digit, i.e. "2 3 4 "
or "2 3 4\n" */
if ( *ptr == 0 ) break;
int x = 0;
while ( isdigit(*ptr) ) {
x = x * 10 + (*ptr - '0');
++ptr;
}
printf("%d\n", x);
}
same output as C++ version
Hope it helps,
Carlos Guía
On Mon, May 17, 2010 at 3:41 AM, maverick gugu <[email protected]>wrote:
> Hi All,
> Sorry that I'm pulling an old problem up. With reference to GCJ 09, round
> 1A problem a(Multi-base Happiness)
> URL: http://code.google.com/codejam/contest/dashboard?c=188266#s=p0
>
> How does one accept an arbitrary set of integers as input?
> -By reading an entire line and processing number by number is one method.
> But the problem is for two digit numbers..
>
> Just checked the code of others, but would be really nice if someone can
> explain it out more clearly in C/C++.(C would be great.)
> Thank you.
>
> -Maverick
>
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