I'm really sorry, my mistake. I always get a compile error while I write .find and I never remember the correct way of how it works.
On Fri, May 13, 2011 at 2:20 PM, Axel Freyn <[email protected]> wrote: > Just a small remark: > > On Fri, May 13, 2011 at 6:56 PM, Leopoldo Taravilse > <[email protected]>wrote: > >> Here's an example >> >> set<int> setint; // you create a set >> setint.insert(4); // you add 4 to the set in o(log n) where n is the >> number of elements of the set >> setint.insert(5); // you add 5 to the set >> setint.insert(4); // nothing happens because 4 is already in the set >> if(setint.find(4)) cout << "4 is in the set" << endl; // you check in >> o(log n) if 4 is in the set, and because it is in the set you print "4 is in >> the set". >> setint.clear(); // you clear the set in o(1). >> > > setint.find(4) > returns an iterator -- so you can't use it in an if-clause. You should > write > if(setint.find(4) != setfind.end() ) > instead (if the key 4 is NOT found, "find" will compare equal to > setfind.end()) > > > -- > You received this message because you are subscribed to the Google Groups > "google-codejam" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/google-code?hl=en. > -- You received this message because you are subscribed to the Google Groups "google-codejam" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-code?hl=en.
