cow=1
bull=19
goat=80.
You can solve with with the help of
x+y+z=100
x+5y+z/20=100
replace x=100-y-z in eq 2.
you will get y/z=19/80.
i.e. ratio of bull and goad should be 19:80.
hence you can keep bull=19
and goat =80
remaining 1 will be cow.








Er. Sudhir Yadav
Sasken Communication Technologies
Bangalore-47



On Fri, Aug 10, 2012 at 3:11 PM, Paul Smith <[email protected]> wrote:

> b = number of bulls bought
> c = number of cows bought
> g = number of batches of 20 goats bought
>
> So you need to spend your $100? => c + 5b + g = 100
> You need to have 100 animals? => c + b + 20g = 100
> You need at least 1 of each animal? => c > 0, b > 0, g > 0
>
> Looks like a simplex problem to me?
>
> Paul Smith
>
> [email protected]
>
>
> On Fri, Aug 10, 2012 at 7:44 AM, Bonethug <[email protected]> wrote:
> > You have $100. You need to buy cows, bulls and goats which sell at the
> > following rate.
> > $1 = 1 Cow
> > $5 = 1 Bull
> > $1 = 20 Goats
> > How will you purchase these animals so that you spend your $100 and you
> have
> > 100 animals which includes the cows, bulls and goats.
> > A pretty tough question for more google code community, I need help,
> > Thanks and Regards,
> > Bonethug
> >
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