On Thursday, April 11, 2019 at 12:21:58 AM UTC+5:30, F S wrote:
> On Monday, April 8, 2019 at 10:40:24 PM UTC+2, Abhishek Kalahal wrote:
> > RE means a runtime error happened, not an issue of time since the judge
> > would've just said TLE (Time Limit Exceeded) if that was the case.
> >
> > My program probably would've gotten a TLE for the hidden test set but it
> > shouldn't be an issue for the first set, where the highest valued prime
> > wouldn't exceed 10,000.
> >
> > By the way Ralph, could you provide an example for the issue you stated?
> > Were you referring to cases like ABA, where the first two numbers in the
> > cipher text would be the same? I tried to account for that by including the
> > statement "decipher = decipher [::-1]"
>
> First, your program prints something before the Case. This will make it fail.
>
> Second, your program doesn't work on:
>
> 1
> 107 29
> 15 15 15 15 21 49 77 143 221 323 437 667 899 1147 1517 1763 2021 2491 3127
> 3599 4087 4757 5183 5767 6557 7387 8633 9797 10403
>
> It outputs "CACACBFDIEMFRGSHTJUKVLWNXOYPZQ", while the correct answer is
> "ABABACCDEFGHIJKLMNOPQRSTUVWXYZ"
you can check my code that gives correct answer..still shows RE in codejam
unacceptable..
def factors(n):
ls=[]
for i in range(2,n//2):
if n%i==0:
ls.append(i)
break
ls.append(n//i)
return ls
t=int(input())
#start_time = time.time()
for ix in range(1,t+1):
n,l=map(int,input().rstrip().split(" "))
s=str(input().rstrip())
ls=list(s.split(" "))
j=0
dict={}
al=[]
nm=[]
for i in range(65,92):
al.append(chr(i))
fls=[]
for i in ls:
fls.append(factors(int(i)))
l=factors(int(ls[0]))
if int(ls[1])%l[0]==0:
pv=l[0]
ov=l[1]
else:
pv=l[1]
ov=l[0]
lll=[]
lll.append(ov)
lll.append(pv)
for i in range(1,len(ls)):
pv=int(ls[i])//pv
lll.append(pv)
llp=sorted(list(set(lll)))
llt=[]
for i in lll:
llt.append(al[llp.index(i)])
strg="".join(llt)
print("Case #{}: {}".format(ix,strg))
#print("--- %s seconds ---" % (time.time() - start_time))
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