*Here's my code:*
import re
import random
def missing_number(k, N):
if not (1 < int(N) < 10**100) or '4' not in N:
print()
return
pos = [i.start(0) for i in re.finditer('4', N)]
inter_list = [i for i in N]
for i in pos:
inter_list[i] = str(random.randint(1, 3))
val = int(''.join(inter_list))
diff = int(N) - val
print(f'Case #{k+1}:', diff, val)
t = int(input())
l = [input() for i in range(t)]
for t, N in enumerate(l):
missing_number(t, N)
*Output* (On my system)
3
414
12345678
123131231231312313
Case #1: 203 211
Case #2: 30000 12315678
"If there are multiple solutions, you may output any one of them"
>
The answers are correct right....?
Then why do I get a RE? How should I solve it?
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