Hi!
Thanks for your help,
I don't really know much about this... How would I add this to my
current code?
CODE:
<view height="117" width="170" onopen="view_onOpen()">
<img height="117" width="170" src="stock_images\background.png"/>
<img dropTarget="true" enabled="true" height="62" hitTest="htclient"
width="170" src="stock_images\lfs-logo.png"/>
<img dropTarget="true" enabled="true" height="15" hitTest="htclient"
width="170" y="62" src="stock_images\top.png"/>
<img dropTarget="true" enabled="true" height="30" hitTest="htclient"
width="170" y="77" src="http://www.lfs.net/content/inc/
realtime_numbers.php"/>
<img dropTarget="true" enabled="true" height="10" hitTest="htclient"
width="170" y="107" src="stock_images\bottom.png"/>
<a height="62" width="170" href="http://www.lfs.net"/>
<meta http-equiv="refresh" content="60"/>
</view>
On Oct 2, 6:43 am, "Benjamin [API Guru]" <[EMAIL PROTECTED]>
wrote:
> Hi James,
>
> you can use the XMLHttpRequest object to retrieve the image from your
> URL and then set the src attribute of your image to the responseStream
> of your XMLHttpRequest response.
>
> Here is some simple example code. Please note that this code is
> synchronous so you might want to turn this into an asynchronous call
> but it should be better readable and help you understand the concept:
>
> function ajaxPicture(url) {
> var req = new XMLHttpRequest();
> req.open('GET', url, false);
> req.send();
> if (req.status == 200) {
> return req.responseStream;
> }
>
> }
>
> yourimage.src = ajaxPicture('http://www.lfs.net/content/inc/
> realtime_numbers.php');
>
> Best regards,
> Benjamin
>
> On Sep 29, 10:59 am, jamesnorman93 <[EMAIL PROTECTED]> wrote:
>
> > Problems/Can anyone help?
> > - I can't get a php image file to display on my Google Gadget
> > (http://www.lfs.net/content/inc/realtime_numbers.php)
>
> > Does anyone know how to do this?
>
> > Thanks,
> > James
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