Found the solution? I exactly have the same problem.

On Wednesday, November 14, 2012 7:27:47 PM UTC+3:30, David Rothmann wrote:
>
> Hello,
>
> i try to create an album via rest api. Please see my code below. As 
> content i get the message "*Content-Type text/xml is not a valid input 
> type.*"
>
> Do i misunderstood the api?
>
> Link to 
> Api<https://developers.google.com/picasa-web/docs/2.0/developers_guide_protocol#AddAlbums>
>
> public void CreateAlbum()
>         {
>             var client = new RestClient("
> https://picasaweb.google.com/data/feed/api/user/"; + _userId);
>             var request = new RestRequest(Method.POST);
>             request.AddHeader("Authorization", CONST.PIC_AUTH + _token);
>             request.AddHeader("Content-Type", "application/atom+xml");
>             string data = "<entry xmlns='http://www.w3.org/2005/Atom'" +
>                              "xmlns:media='http://search.yahoo.com/mrss/'" 
> +
>                              "xmlns:gphoto='
> http://schemas.google.com/photos/2007'>" +
>                              "<title type='text'>Trip To Italy</title>" +
>                              "<summary type='text'>This was the recent 
> trip I took to Italy.</summary>" +
>                              "<gphoto:location>Italy</gphoto:location>" +
>                              "<gphoto:access>public</gphoto:access>" +
>                             
>  "<gphoto:timestamp>1152255600000</gphoto:timestamp>" +
>                              "<media:group>" +
>                              "<media:keywords>italy, 
> vacation</media:keywords>" +
>                              "</media:group>" +
>                              "<category scheme='
> http://schemas.google.com/g/2005#kind'" +
>                              "term='
> http://schemas.google.com/photos/2007#album'></category>" +
>                              "</entry>";
>
>             request.AddBody(data);
>
>             try
>             {
>                 client.ExecuteAsync(request, (response) =>
>                 {
>
>                     MessageBox.Show(response.Content); //*Content-Type 
> text/xml is not a valid input type.*
>
>                 });
>             }
>             catch (Exception ex)
>             {
>                 MessageBox.Show(ex.Message);
>             }
>
>         }
>

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