The protocol is outlined here:
https://developers.google.com/identity/protocols/OAuth2
I don't see a client library in C# there, but a quick Google search shows
several examples that might work.
On Fri, May 29, 2015, 8:24 AM Mark Otway <m...@otway.com> wrote:
> Not sure, sorry. My Oauth code was in java, and I don't have time to deep
> dive into the C# code right now. Maybe somebody on the list who's done C#
> OAuth might spot what's going on.
>
> On Fri, 29 May 2015 at 16:21 Ben Donovan <bendonovan1...@googlemail.com>
> wrote:
>
>> Hi Mark,
>>
>> Thanks for your quick response. It was a little annoying when this
>> stopped working...but that's the way it goes! I understand what you are
>> saying but is there a reason why my code (using Outh2) is still failing?
>> Isn't this doing basically what the clientlogin was doing before? I have
>> set it up in the developer console, using the P12 key I am collecting the
>> access token which is going to give my application the credentials to
>> access the Picasa account. Am I missing something?
>>
>> Thanks!
>>
>>
>> On Friday, 29 May 2015 16:07:55 UTC+1, Mark Otway wrote:
>>
>>> As far as I’m aware, no, there is no simple way of doing it.
>>>
>>> Remember that while you know it’s your account, Google doesn’t - from
>>> their servers’ perspective you’re just a user making REST requests.
>>> Clearly, Google can’t accept requests to private photos without any form of
>>> authentication.
>>>
>>> Whilst it’s annoying that user/pass auth isn’t supported any more,
>>> writing OAuth isn’t that hard and there are plenty of examples out there.
>>>
>> On 29 May 2015, at 15:44, Ben Donovan <bendono...@googlemail.com> wrote:
>>>
>>> Hi Mark/anyone else,
>>>
>>> Since the setUserCredentials has been deprecated is there any way to
>>> simply connect with your own picasa account to upload photos, without the
>>> need to get user authentication which I don't need since it is my own
>>> account? I have tried the following code and I am still getting the same
>>> error:
>>>
>>> "The remote server returned an error: (404) Not Found." error.
>>>
>>> {"Execution of request failed:
>>> https://picasaweb.google.com/data/feed/api/user/default/albumid/myalbumid
>>> "}
>>>
>>>
>>> -----------------
>>>
>>> My Code:
>>>
>>> Uri postUri = new Uri(PicasaQuery.CreatePicasaUri("default", AlbumID));
>>>
>>>
>>>
>> const string ServiceAccountEmail = "em...@developer.gserviceaccount.com";
>>>
>>
>>>
>>> var certificate = new X509Certificate2(HttpContext
>>> .Current.Server.MapPath("bin/key2.p12"), "notasecret",
>>> X509KeyStorageFlags.Exportable);
>>>
>>>
>>>
>>> var serviceAccountCredentialInitializer = new ServiceAccountCredential.
>>> Initializer(ServiceAccountEmail)
>>>
>>> {
>>>
>>> Scopes = new[] { "
>>> https://picasaweb.google.com/data/"; }
>>>
>>> }.FromCertificate(certificate);
>>>
>>>
>>>
>>> var credential = new ServiceAccountCredential
>>> (serviceAccountCredentialInitializer);
>>>
>>>
>>>
>>> if (!credential.RequestAccessTokenAsync(System.Threading.
>>> CancellationToken.None).Result)
>>>
>>> throw new InvalidOperationException("Access token
>>> request failed.");
>>>
>>>
>>>
>>> var requestFactory = new GDataRequestFactory(null);
>>>
>>> requestFactory.CustomHeaders.Add("Authorization: Bearer
>>> " + credential.Token.AccessToken);
>>>
>>>
>>>
>>>
>>>
>>> PicasaService service = new PicasaService("My App");
>>>
>>> service.RequestFactory = requestFactory;
>>>
>>>
>>>
>>> string sContentType = "image/jpeg";
>>>
>>>
>>>
>>> PicasaEntry entry = (PicasaEntry)service.Insert(postUri, fileStream,
>>> sContentType, sFilename);
>>>
>>>
>>>
>>> fileStream.Close();
>>>
>>>
>>>
>>> sPicasaURL = entry.Media.Content.Url.ToString();
>>>
>>>
>>> Any help would be appreciated.
>>>
>>>
>>> Thanks!
>>>
>>>
>>>
>>> On Friday, 29 May 2015 15:29:43 UTC+1, Francesco Defazio wrote:
>>>>
>>>> Hi all, since 27th May 2015 I'm not able to upload pictures using
>>>> picasa Api.
>>>> I get always the same error:
>>>> Execution of authentication request returned unexpected result: 404
>>>>
>>>> The crediantials it wasn't change and by browser I can login without
>>>> problems.
>>>> My application running succesfully since October 2011.
>>>>
>>>> The code of my application is:
>>>> Dim reqSet As New Google.GData.Client.RequestSettings("GM")
>>>> Dim picasarequest As Google.Picasa.PicasaRequest
>>>> Dim service As New Google.GData.Photos.PicasaService("")
>>>> reqSet.Timeout = 600000
>>>> picasarequest = New Google.Picasa.PicasaRequest(reqSet)
>>>> service = picasarequest.Service
>>>> service.setUserCredentials(PicasaUserName, PicasaPassword)
>>>> reqSet = Nothing
>>>> picasarequest = Nothing
>>>>
>>>> Dim feed As Google.GData.Photos.PicasaFeed
>>>> Dim entry As Google.GData.Photos.PicasaEntry
>>>> Dim postUri As Uri
>>>> Dim album As Google.GData.Photos.AlbumAccessor
>>>> Dim StartIndex As Integer = 1
>>>> Dim AlbumId As String = ""
>>>>
>>>>
>>>> Dim newEntry As New
>>>> Google.GData.Photos.AlbumEntry
>>>> Dim feedUri As Uri
>>>> Dim AlbumSummary As String
>>>>
>>>> AlbumSummary = GetAlbumSummary(AlbumNameCurrent)
>>>> newEntry.Title.Text = AlbumNameCurrent
>>>> newEntry.Summary.Text = AlbumSummary
>>>> album = New
>>>> Google.GData.Photos.AlbumAccessor(newEntry)
>>>>
>>>> If PhotoTypeCurrent = enPhotoType.Shipment Then
>>>> album.Access = "private"
>>>> Else
>>>> album.Access = "public"
>>>> End If
>>>>
>>>> feedUri = New
>>>> Uri(Google.GData.Photos.PicasaQuery.CreatePicasaUri(PicasaUserName))
>>>> album = New
>>>> Google.GData.Photos.AlbumAccessor(service.Insert(feedUri, newEntry))
>>>>
>>>> I got the error in the last operation:
>>>> album = New
>>>> Google.GData.Photos.AlbumAccessor(service.Insert(feedUri, newEntry))
>>>>
>>>> I also get the error with: feed = service.Query(query)
>>>>
>>>> Dim query As Google.GData.Photos.AlbumQuery
>>>> Dim feed As Google.GData.Photos.PicasaFeed
>>>>
>>>> query = New
>>>> Google.GData.Photos.AlbumQuery(Google.GData.Photos.PicasaQuery.CreatePicasaUri(PicasaUserName))
>>>> query.StartIndex = 1
>>>> query.NumberToRetrieve = 1000
>>>> feed = service.Query(query)
>>>>
>>>> Thank in advance
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
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