Hi, Swanand
Thank you very much for your help, I understand the problem  further
more. Now my problem is about the call example itself:
After loging in (of course, using call example with "-d"
option ),,then someone else adds me as his/her friend
, here  comes  the  problem, my  server  did  not  send  me  a
notification  about  this  event ,.:

If I log out and then log in this account again with GTalk or some
other client, then I will get the notification of this event, so I am
sure that my server did not send me anything in the first condition.
(just save it until I log in with GTalk or some other client), Do you
think so?  I need your help with this problem, thank you very much.

Best wishes.
On Oct 26, 3:16 am, "swanand rao" <[EMAIL PROTECTED]> wrote:
> Hi Water2Oil,
>
> Check out the RFC for XMPPhttp://www.ietf.org/rfc/rfc3921.txthave a look
> at section 5.1.6 and section 8 it has the details which ur looking for. I am
> sure it will help you.
>
> Regards,
>
> Swanand
>
> On 10/25/07, water2oil <[EMAIL PROTECTED]> wrote:
>
>
>
> > Hi,
>
> > First ,take the following steps:
> > 1, Running the call example in libjingle with "-d" option (for
> > example, log in as    [EMAIL PROTECTED])
>
> > 2, then [EMAIL PROTECTED] send a request to add me as his/her friend
>
> > the problem is :
>
> > I receive nothing infomation on screen, so how do I know that
> > [EMAIL PROTECTED] wants to add me now?????
>
> > maybe we can say in another way:
> > 1, if I want to add someone else as my friend, we can send
> >    <iq type='set'>
> >      <query xmlns='jabber:iq:roster'>
> >        <item jid='[EMAIL PROTECTED]'/>
> >      </query>
> >    </iq>
> > to "our server". but "our server" must sends something to notify the
> > "someone else".
> > what infomation is sent by "our server"? OR what information "someone
> > else" receives?
>
> > I don't know if my expression is clearly, forgive my poor english.
>
> > Anyone would give me some hints? thanks in advance.


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