Ok, I understand that. Thanks.
What if I just want to display the chart with out directly connected
to a control. Would it be possible to do that?
Thanks.
On Dec 30 2011, 4:04 am, ChartMan <chart...@google.com> wrote:
> Hey
>
> If you look up the API you can see that you bind control/s to chart/s. The
> example below tries to bind two charts which is probably the cause for this
> error.
>
> HTH
> ChartMan
> On Dec 30, 2011 2:32 AM, "MrTik" <hetan.s...@gmail.com> wrote:
>
>
>
>
>
>
>
> > Here is the code that I am trying to render, however I get the
> > mentioned error.
>
> > function rDetailQueryResponse(response) {
> > if (response.isError()) {
> > alert('Error in query: ' + response.getMessage() + ' '
> > +response.getDetailedMessage());
> > return;
> > }
> > mResultDetails = response.getDataTable();
> > var mDrawData2 = new
> > google.visualization.Table(document.getElementById('visualization2'));
>
> > mDataJoin = new
> > google.visualization.data.join(mResultDetails,mDriverName,'left',
> > [[1,1],[2,2],[3,3],[4,4]],[5,6,7,8,9,10,11,12,13,14,15,16],[5]);
>
> > // Define a chart to show data
> > var columnChart = new
> > google.visualization.ChartWrapper({
> > 'chartType': 'ColumnChart',
> > 'containerId': 'chart3',
> > 'options': {
> > 'width': 1500,
> > 'height': 800,
> > 'legend': 'right',
> > 'isStacked': true,
> > 'title': 'Forward Costs Initiatives
> > Impact',
> > 'seriesType': 'bars',
> > 'series': {7: {type: 'line'}, 8:
> > {type: 'line'}, 9: {type:
> > 'line'}}
> > },
> > // Configure the barchart to use columns
> > 'view': {'columns': [4, 5, 6, 7, 8, 9, 10,
> > 11, 12, 13, 14]}
> > });
>
> > //Define a table
> > var table = new google.visualization.ChartWrapper({
> > 'chartType': 'Table',
> > 'containerId': 'chart2',
> > 'options': {
> > 'width': '1500'
> > },
> > // Configure the barchart to use columns
> > 'view': {'columns': [0, 1, 2, 3, 4, 5, 6,
> > 7, 8, 9, 10, 11, 12, 13,
> > 14]}
> > });
>
> > new
>
> > google.visualization.Dashboard(document.getElementById('visualization')).bind([columnChart,
> > table]).draw(mDataJoin);
>
> > }
>
> > Any thoughts as to why I would get this error?
>
> > Thanks.
>
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