Hi,
i have still problem with post data...
in attach my files.
when i set "date from" and click submit, files "goo2.php" generates correct 
array, but this array is not import back to "index.php".
Please could somebody help me? :(


W dniu czwartek, 13 grudnia 2012 08:22:00 UTC+1 użytkownik Chrystopher 
Medina napisał:
>
>
>
> i didn´t understand very well ... excuse me. but 
>  this is my new json array : 
>
> {"cols":[{"label":"Type","type":"string"},{"label":"Count","type":"number"},{"label":"Aspecto","type":"number"}],"rows":[{"c":[{"v":"excelent"},{"v":1}]},{"c":[{"v":"good"},{"v":2}]},{"c":[{"v":"fair"},{"v":1}]},{"c":[{"v":"poor"},{"v":1}]},{"c":[{"v":"word
>  
> of mouth recomendation"},{"v":3}]},{"c":[{"v":"magazine 
> advertisement"},{"v":1}]},{"c":[{"v":"roadside 
> advertisement"},{"v":1}]},{"c":[{"v":"google"},{"v":3}]}]}.
>
> this is my php file:
>
> <?php 
> $var1="$_POST[fecha1]";
>
> $var2= "$_POST[fecha2]";
>
> $server="localhost";
> $username="root";
> $password="chrystopher";
> $databasename="encuestasavandaro";
>
> $con = mysql_connect($server,$username,$password) or die ('Error 
> connecting to server');
> mysql_select_db($databasename,$con);
>
> $query = "SELECT b.id_respuesta , COUNT(b.id_respuesta) AS cnt, 
> b.id_aspecto
> FROM huesped a, rompe_encuesta b
> WHERE
> b.id_huesped = a.id_huesped AND
> ((b.id_aspecto = 1 AND b.id_respuesta >= 8 AND b.id_respuesta <= 11) 
> OR 
> (b.id_aspecto = 2 AND b.id_respuesta >= 1 AND b.id_respuesta <= 4))
> AND
> a.fecha BETWEEN '2012-12-01' AND '2012-12-12'
> GROUP BY b.id_respuesta;";
>
>
> $table = array();
>
> $table['cols']=array(
> array('label' => 'Type' , 'type' => 'string'),
>  array('label' => 'Count' , 'type' => 'number'),
>         array('label' => 'Aspecto', 'type' => 'number')
> );
>
> $rows = array();
>  if (!mysql_query($query,$con))
>   {
>   die('Error: ' . mysql_error());
>   }else{
>       
>       $sqlquery= mysql_query($query);
> while($r = mysql_fetch_assoc($sqlquery)){
>     $temp = array();
> // using (int) $variable typecasts the variable as an integer, usefull 
> when the SQL is returning numbers as strings
>    
>     switch ((int) $r['id_respuesta']) {
>                 
>                 case 1:
>                         $type='excelent';
>                         break;
>                 case 2:
>                         $type='good';
>                         break;;
>                 case 3:
>                         $type='fair';
>                         break;
>                 case 4:
>                         $type='poor';
>                         break;
>         
> case 8:
>  $type = 'word of mouth recomendation';
> break;
>  case 9:
> $type = 'magazine advertisement';
>  break;
> case 10:
> $type = 'roadside advertisement';
>  break;
>                     case 11:
> $type = 'google';
>  break;
>                     default:
> die('{"error":"Error in SQL query: unknown \'id_respuesta\'"}');
>  }
>
>     $temp[] = array('v' => $type);
>     $temp[] = array('v' => (int) $r['cnt']);
>     $rows[] = array('c' => $temp);
> }
>   }
> $table['rows'] = $rows;
>
> $jsonTable = json_encode($table);
> echo $jsonTable;
>
> ?>
>
>

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