In my situation the code is in If block
if( true) {
popup.show();
store.load() // it takes 5-6 sec.
// It is sequence of steps like server calls, developing front end,
other processing.
popup.hide();
}
If i execute it like this popup is not shown because popup.show & hide
both are executing at a time.
I removed popup.hide() to know whether popup is shown or not? It is
showing popup after completion of all the process it shows popup.
( after execution of IF block)
How handle this situation???/
Thanks
Rohan
On Jul 8, 10:42 am, Mikhail M <itmo....@gmail.com> wrote:
> I suppose you should use listeners. And call method popup.hide(); in right
> place
> For example
> popup.show();
> store.load() // it takes 5-6 sec.
> popup.hide();
> INCORRECT
>
> but
> popup.show();
> store.addListener(new StoreListenerAdapter() {
> @Override
> onLoad() {
> popup.hide();
> }});
>
> works properly
>
> Check your source code once more and use listeners
>
> 2009/7/8 rohan <subbu.ge...@gmail.com>
>
>
>
>
>
> > I am showing transparent screen using a popup.
>
> > On an onclick event of a button Iam showing a popup in an ‘if’ block,
> > but the popup is only shown when if returns from the if block, why it
> > behaves like this? Is there any other way to show a popup in an ‘if’
> > block?
>
> > Below is the code
>
> > if(Condition){
> > popup.show();
> > do some work;//// it takes 5-6 sec. This time my screen is blocked
> > with popup
> > popup.hide();
>
> > }
>
> > But it is not working, If i remove popup.hide(), popup is shown after
> > the IF block executed. So at that time it is useless
>
> > Can any one help me in this.
>
> > Thanks
> > Rohan
>
> --
> Best wishes
> Mikhail Mamaev
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