Thanks manuel for your reply. I tried gwtupload. It was not working for me but I suspect it was because of the configuration. Since I am very close to my goal using the files I currently have, I would like to be able to make this very simple example work and understand how it works before going into more complicated things. The upload is working fine so far in hosted mode, but still no luck with the website on the server. I have another question. At the beginning of this thread you told to twittwit to use item.getName() to get the name of the file he wanted to upload. However for me, getName() and getFieldName() both return the name of the field which is uploadFormElement in my case.
On Aug 4, 7:53 am, Manuel Carrasco Moñino <manuel.carrasc...@gmail.com> wrote: > Perhaps, you could use gwtupload <http://code.google.com/p/gwtupload/> which > simplifies this process and has documentation about configuring your server > side. > > Manolo Carrasco > > > > > > On Mon, Aug 3, 2009 at 8:12 AM, Vinz369<vincentriv...@gmail.com> wrote: > > > Hi twittwit, > > And thanks for your reply. > > What I want is quite simple. I want to be able to place a button in my > > UI. When he user clicks on this button he can retrieve a file on his > > machine and clicking another button it will upload it to the server > > hosting the website. > > I tried with fileupload from gwt, gwt-ext, and others but I usually > > get the error that my server code is not found when I click on the > > upload button. > > Would it be possible to know step by step how should I proceed? > > > On Aug 2, 10:09 pm, twittwit <ytbr...@gmail.com> wrote: > >> if you mean common fileupload. it should be at the server. > >> nope for web.xml. and nope for project.gwt.xml --> since you putting > >> common fileupload to the server. > >> try to be more clear ini what u want? and where is the problem. > > >> On Jul 21, 4:13 pm, Vinz369 <vincentriv...@gmail.com> wrote: > > >> > Hello twittwit and others, > > >> > I've been trying to implement fileuploadfor days in my application. > >> > It may looks stupid but I really don't understand how it works. > >> > I have few questions: > >> > - If I want to use the same code as twittwit where should I place it? > >> > in my client folder or server folder? should I add something else in > >> > my web.xml and project.gwt.xml files? > > >> > I'm completely lost, please help me! > > >> > On Jul 18, 10:15 am, twittwit <ytbr...@gmail.com> wrote: > > >> > > perfect! thanks Manuel! > >> > > common-fileupload is great! > >> > > On Jul 18, 8:51 am, Manuel Carrasco <manuel.carrasc...@gmail.com> > >> > > wrote: > > >> > > > filename = item.getName(); > > >> > > > On Sat, Jul 18, 2009 at 12:27 AM, twittwit <ytbr...@gmail.com> > wrote: > > >> > > > > ok thank you. i found the answer: > > >> > > > > public class MyFormHandler extends HttpServlet{ > >> > > > > public void doPost(HttpServletRequest request, > > HttpServletResponse>> > > > > response) throws ServletException, IOException > { > >> > > > > ServletFileUploadupload= new ServletFileUpload(); > > >> > > > > try{ > >> > > > > FileItemIterator iter > > =upload.getItemIterator(request); > > >> > > > > while (iter.hasNext()) { > >> > > > > FileItemStream item = iter.next(); > > >> > > > > String name = item.getFieldName(); > >> > > > > InputStream stream = item.openStream(); > > >> > > > > // Process the input stream > >> > > > > FileOutputStream out = new FileOutputStream > >> > > > > ("example.csv"); > >> > > > > //ByteArrayOutputStream out = new > > ByteArrayOutputStream > > > > >> > > > > (); > >> > > > > int len; > >> > > > > byte[] buffer = new byte[8192]; > >> > > > > while ((len = stream.read(buffer, 0, > buffer.length)) ! > >> > > > > = -1) { > >> > > > > out.write(buffer, 0, len); > >> > > > > } > >> > > > > //....... > > >> > > > > } > >> > > > > } > >> > > > > catch(Exception e){ > >> > > > > e.printStackTrace(); > >> > > > > } > > >> > > > > } > > >> > > > > } > > >> > > > > however, how can i extract the name of the csv file(client side) > so > >> > > > > that the csv file in my server can have the same name? > >> > > > > thanks!! > > >> > > > > On Jul 18, 12:19 am, Manuel Carrasco <manuel.carrasc...@gmail.com > > >> > > > > wrote: > >> > > > > > In the dialog between the browser and the server, the client > sends a > >> > > > > > multipart/form-data request and there is more information > besides the > >> > > > > file > >> > > > > > content, like form elements values, boundary tags, etc. > > >> > > > > > I recommend you to use apache commons-fileupload library to > handle > >> > > > > > multipart/form-data request in your servlets. > > >> > > > > > On Fri, Jul 17, 2009 at 11:44 PM, imgnik <ytbr...@gmail.com> > wrote: > > >> > > > > > > hi all, > > >> > > > > > > i posted a question about fileupload here > > http://groups.google.com/group/Google-Web-Toolkit/browse_thread/threa. > > > > >> > > > > .. > >> > > > > > > but i think i didn't phrase my question correctly. so gonna > do another > >> > > > > > > attempt. > > >> > > > > > > I tried to use agwtfileupload widget to send a csv file to > the > >> > > > > > > server. and at the server i will write it as a file (for > other usage) > >> > > > > > > it by doing : (where request is the httpservletrequest and bw > is the > >> > > > > > > bufferedwriter) > > >> > > > > > > BufferedReader r = request.getReader(); > >> > > > > > > while((thisread= r.readLine())!=null){ > > >> > > > > > > bw.write(thisread); > > >> > > > > > > } > >> > > > > > > bw.close(); > >> > > > > > > } > >> > > > > > > catch(Exception e1){} > > >> > > > > > > however, i realised that the csv file send out contains : > > >> > > > > > > ------WebKitFormBoundaryN8Z6DOy7DqEWTwtLContent-Disposition: > form- > >> > > > > > > data; name="uploadFormElement"; > > filename="first.csv"Content-Type: > > > > >> > > > > > > application/octet-streamBank > > >> > > > > > > which results in the file created not the same as the > fileupload. > >> > > > > > > I might be wrong in my analysis. can someone advice me? 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