Ok, here is what Google said (
https://developers.google.com/webmasters/ajax-crawling/docs/getting-started
).
When a crawler sees a url like this www.example.com/ajax.html#!key=value,
it will temporarily convert that url into
www.example.com/ajax.html?_escaped_fragment_=key=value
However, when doing that it also escapes certain characters in the fragment
during the transformation. Ex: www.example.com/ajax.html#!key=value;car=%to
www.example.com/ajax.html?_escaped_fragment_=key=value;car=%25
so if we want to convert
www.example.com/ajax.html?_escaped_fragment_=key=value;car=%25 back to the
original url then we need to unescape all %XX characters in the fragment.
Google said:
Note: The crawler escapes certain characters in the fragment during the
transformation. To retrieve the original fragment, make sure to unescape
all %XX characters in the fragment. More specifically, %26 should become &,
%20 should become a space, %23 should become #, and %25 should become %,
and so on.
But google doesn't say How to do that in java.
String originalUrl=changedStr.replace("?_escaped_fragment_=", "!#");// then
what to do next so that all the escaped characters will go back to normal?
http://stackoverflow.com/questions/23692748/the-crawler-escapes-mydomainarticle-into-mydomain-escaped-fragment-articl
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