Thanks for the quick reply! Great, happy to be of some help. This means that
we now get the following:
```python
L1 = -state.entropy()
L2 = -state_ln.entropy() - np.log(g.ep.weight.a).sum()
print("Exponential model:\t", L1) # Exponential model: 7201.52
print("Log-normal model:\t", L2) # Log-normal model: 7230.95
print(u"ln \u039b:\t\t\t", L2 - L1) # ln Λ: 29.42
```
So it is still true that the exponential model does not provide a better fit
for the data, but not by much!
Cheers,
Jonathan
--
Sent from: https://nabble.skewed.de/
_______________________________________________
graph-tool mailing list
graph-tool@skewed.de
https://lists.skewed.de/mailman/listinfo/graph-tool
