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Today's Topics:
1. grass_width, grass_heigt and grass_pngfile (Liu, Huili)
2. Re: grass_width, grass_heigt and grass_pngfile (Markus Neteler)
3. Re: grass_width, grass_heigt and grass_pngfile (Glynn Clements)
----------------------------------------------------------------------
Message: 1
Date: Fri, 2 Mar 2012 20:27:46 +0000
From: "Liu, Huili" <h...@ap.org>
Subject: [GRASS-windows] grass_width, grass_heigt and grass_pngfile
To: "grass-windows@lists.osgeo.org" <grass-windows@lists.osgeo.org>
Message-ID:
<edbb02efb114934ea2fa741873e8a5251344c...@ctcxmbx01.ap.org>
Content-Type: text/plain; charset="us-ascii"
Hi grass experts,
I am trying to create a python script to get an image file as below:
#get_img.py
import os.path
import sys # the sys module [2]
from grass.script import core as grass # the core module [3]
def main():
grass.run_command('d.his i=elevation_shade h=elevation')
if __name__ == "__main__": # this allows the script to be used as a module in
other scripts or as a standalone script
#options, flags = grass.parser() #
sys.exit(main())
But I got the default image file name, map.png with GRASS_WIDTH=640 and
GRASS_HEIGHT=480.
Is there any way for me to setup width and height and my image file name in
grass.run_command?
I searched the doc for a while but I still can not get a correct syntax.
Thanks for an advance!
Willie
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------------------------------
Message: 2
Date: Sat, 3 Mar 2012 06:19:44 +0100
From: Markus Neteler <nete...@osgeo.org>
Subject: Re: [GRASS-windows] grass_width, grass_heigt and
grass_pngfile
To: "Liu, Huili" <h...@ap.org>
Cc: "grass-windows@lists.osgeo.org" <grass-windows@lists.osgeo.org>
Message-ID:
<calfmhhshdbgjyzwkrson66xuwuv60qiy62smkfmxzb5+x+a...@mail.gmail.com>
Content-Type: text/plain; charset=ISO-8859-1
Hi Willie,
On Fri, Mar 2, 2012 at 9:27 PM, Liu, Huili <h...@ap.org> wrote:
>
> I am trying to create a python script to get an image file as below:
>
...
>
> But I got the default image file name, map.png with GRASS_WIDTH=640 and
> GRASS_HEIGHT=480.
>
> Is there any way for me to setup width and height and my image file name in
> grass.run_command?
You need to set these two environment variables
GRASS_WIDTH=xxx
the width of the image map (default is 640).
GRASS_HEIGHT=yyy
the height of the image map (default is 480).
See
http://grass.osgeo.org/grass64/manuals/html64_user/pngdriver.html
Hope this helps,
Markus
------------------------------
Message: 3
Date: Sat, 3 Mar 2012 16:15:08 +0000
From: Glynn Clements <gl...@gclements.plus.com>
Subject: Re: [GRASS-windows] grass_width, grass_heigt and
grass_pngfile
To: "Liu, Huili" <h...@ap.org>
Cc: "grass-windows@lists.osgeo.org" <grass-windows@lists.osgeo.org>
Message-ID: <20306.17292.352299.565...@cerise.gclements.plus.com>
Content-Type: text/plain; charset=us-ascii
Liu, Huili wrote:
> I am trying to create a python script to get an image file as below:
>
> #get_img.py
> import os.path
> import sys # the sys module [2]
> from grass.script import core as grass # the core module [3]
> def main():
> grass.run_command('d.his i=elevation_shade h=elevation')
This is wrong; it should be:
grass.run_command('d.his', i='elevation_shade', h='elevation')
> if __name__ == "__main__": # this allows the script to be used as a module in
> other scripts or as a standalone script
> #options, flags = grass.parser() #
> sys.exit(main())
>
> But I got the default image file name, map.png with GRASS_WIDTH=640 and
> GRASS_HEIGHT=480.
> Is there any way for me to setup width and height and my image file name in
> grass.run_command?
> I searched the doc for a while but I still can not get a correct syntax.
import os
os.environ['GRASS_PNGFILE'] = filename
os.environ['GRASS_WIDTH'] = str(width)
os.environ['GRASS_HEIGHT'] = str(height)
--
Glynn Clements <gl...@gclements.plus.com>
------------------------------
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