Am 06.05.2021 um 07:42 schrieb atecon:
Hi all,I just would like to ask whether this behavior is actually expected: <hansl> matrix m = {1, NA; 2, 3} print m eval cum(m) ? print m m (2 x 2) 1 nan 2 3 ? eval cum(m) 1 nan 3 nan </hansl> I expected the entry (2,2) to be 3 as this is the first valid value of the 2nd column.
I'd say it's expected because nans propagate. Basically you don't know what 3 + nan is. To get what you want, I was going to say "do cum(misszero(m))", but that doesn't work on a matrix. Maybe it should? (But remember the old fact that a NaN and a missing value is not always the same thing.) cheers sven _______________________________________________ Gretl-devel mailing list -- gretl-devel@gretlml.univpm.it To unsubscribe send an email to gretl-devel-le...@gretlml.univpm.it Website: https://gretlml.univpm.it/postorius/lists/gretl-devel.gretlml.univpm.it/
