Hi Henrique, I believe that this does what you want: loop for (n=6; n<=24; n*=2) --quiet
No other simple options. On Tue, May 25, 2010 at 8:53 PM, Henrique Andrade <henrique.coelho(a)gmail.com > wrote: > Dear Riccardo, Kehl and Artur, > > Thanks a lot for your help! I'd tried all the options you gave me and > my final script looks like this: > > <script> > scalar n=0 > loop for (n=6;n<=24;n=n*2) --quiet > scalar m = $T - n + 1 > loop j=2..nelemY --quiet > matrix R$n_$j = zeros(m,1) > loop i=1..m --quiet > loop c=1..n --quiet > row = i + n - c > R$n_$j[i] += r$j[row, c] > endloop > endloop > endloop > matrix mci$n = R$n_2 + R$n_3 > endloop > </script> > > Now, because I just need the values for 6, 12 and 24, I'm trying to > substitute the second line "loop for (n=6;n<=24;n=n*2)" for this: > > loop for (n=6;n=12;n=24) > > But the script isn't working. Any hints? > > Best regards, > Henrique > > > 2010/5/25 artur bala <artur.bala(a)laposte.net> > > Or, if your index is something like of a geometric series as it seems to >> be (let's say 6, 12, 24, 48, and so on) and too long to do manually >> you can try this one: >> <script> >> scalar count=0 >> loop for (count=6;count<=24;count=count*2) --quiet >> <instructions> >> endloop >> <\script> >> >> cheers, >> artur >> >> Riccardo (Jack) Lucchetti a écrit : >> > On Tue, 25 May 2010, Henrique Andrade wrote: >> > >> >> Dear Gretl Community, >> >> >> >> I'm trying to use a loop index inside a script but I don't know how. >> >> According >> >> to "Gretl User’s Guide" the syntax looks like this: >> >> >> >> loop i=1..24 >> >> >> >> But I just need the points where "i" is equal to 6, 12 and 24. >> >> Something like this: >> >> >> >> loop i=6;12;24 >> >> >> >> How can I do that? >> > >> > For example, this way: >> > <script> >> > matrix foo = { 6, 12, 24 } >> > n = cols(foo) >> > loop for i=1..n >> > bar = foo[i] >> > print bar >> > end loop >> > </script> >> > >> > >> > Riccardo (Jack) Lucchetti >> > Dipartimento di Economia >> > Università Politecnica delle Marche >> > >> > r.lucchetti(a)univpm.it >> > http://www.econ.univpm.it/lucchetti >> > ------------------------------------------------------------------------ >> > >> > _______________________________________________ >> > Gretl-users mailing list >> > Gretl-users(a)lists.wfu.edu >> > http://lists.wfu.edu/mailman/listinfo/gretl-users >> >> >> _______________________________________________ >> Gretl-users mailing list >> Gretl-users(a)lists.wfu.edu >> http://lists.wfu.edu/mailman/listinfo/gretl-users >> > > > > -- > Henrique C. de Andrade > Doutorando em Economia Aplicada > Universidade Federal do Rio Grande do Sul > www.ufrgs.br/ppge > > _______________________________________________ > Gretl-users mailing list > Gretl-users(a)lists.wfu.edu > http://lists.wfu.edu/mailman/listinfo/gretl-users >Hi Henrique,
I believe that this does what you want:
loop for (n=6; n<=24; n*=2) --quiet
No other simple options.
On Tue, May 25, 2010 at 8:53 PM, Henrique Andrade <henrique.coe...@gmail.com> wrote:
Dear Riccardo, Kehl and Artur,
Thanks a lot for your help! I'd tried all the options you gave me and
my final script looks like this:
<script>
scalar n=0
loop for (n=6;n<=24;n=n*2) --quiet
   scalar m = $T - n + 1
   loop j=2..nelemY --quiet
       matrix R$n_$j = zeros(m,1)
       loop i=1..m --quiet
           loop c=1..n --quiet
               row = i + n - c
               R$n_$j[i] += r$j[row, c]
           endloop
       endloop
   endloop
   matrix mci$n = R$n_2 + R$n_3
endloop
</script>
Now, because I just need the values for 6, 12 and 24, I'm trying to
substitute the second line "loop for (n=6;n<=24;n=n*2)" for this:
loop for (n=6;n=12;n=24)
But the script isn't working. Any hints?
Best regards,
Henrique2010/5/25 artur bala <artur.b...@laposte.net>
Or, if your index is something like of a geometric series as it seems to
be (let's say 6, 12, 24, 48, and so on) and too long to do manually
you can try this one:
<script>
scalar count=0
loop for (count=6;count<=24;count=count*2) --quiet
  <instructions>
endloop
<\script>
cheers,
artur
Riccardo (Jack) Lucchetti a écrit :
> ------------------------------------------------------------------------> On Tue, 25 May 2010, Henrique Andrade wrote:
>
>> Dear Gretl Community,
>>
>> I'm trying to use a loop index inside a script but I don't know how.
>> According
>> to "Gretl Userâs Guide" the syntax looks like this:
>>
>> loop i=1..24
>>
>> But I just need the points where "i" is equal to 6, 12 and 24.
>> Something like this:
>>
>> loop i=6;12;24
>>
>> How can I do that?
>
> For example, this way:
> <script>
> matrix foo = { 6, 12, 24 }
> n = cols(foo)
> loop for i=1..n
> Â Â bar = foo[i]
> Â Â print bar
> end loop
> </script>
>
>
> Riccardo (Jack) Lucchetti
> Dipartimento di Economia
> Università Politecnica delle Marche
>
> r.lucche...@univpm.it
> http://www.econ.univpm.it/lucchetti
>
> _______________________________________________
> Gretl-users mailing list
> gretl-us...@lists.wfu.edu
> http://lists.wfu.edu/mailman/listinfo/gretl-users
_______________________________________________
Gretl-users mailing list
gretl-us...@lists.wfu.edu
http://lists.wfu.edu/mailman/listinfo/gretl-users
--Henrique C. de Andrade
Doutorando em Economia Aplicada
Universidade Federal do Rio Grande do Sul
www.ufrgs.br/ppge
_______________________________________________
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