You were right, it's much faster when I only calculate free energy for one 
molecule. My simulation has 1000 water molecules in it, but I created a new 
topology file and gave one molecule a different name (but identical properties) 
and now it runs the same simulation in about 36% more time, which is much more 
manageable. Thank you very much for the help! I don't think there is a problem 
with my topology or mdp files now. 

Regards,
Nathan H.

----- Original Message -----
From: "Michael Shirts" <mrshi...@gmail.com>
To: "Discussion list for GROMACS users" <gmx-us...@gromacs.org>
Sent: Wednesday, October 7, 2015 11:14:29 PM
Subject: Re: [gmx-users] Free Energy of Liquid Water

If ALL the particles are changing with the free energy coupling
parameter, then GROMACS will slow down quite a bit.  If only one
molecule is changing, then it shouldn't be that much slower (20-30%
slower?)  But without .mdp and.top files, it's hard to say exactly
what is happening.


On Wed, Oct 7, 2015 at 11:08 PM, Nathan K Houtz <nho...@purdue.edu> wrote:
> Thanks for explaining, (and Professor Farais de Moura as well) that makes 
> sense.
>
> On a different note, I've noticed a huge difference in performance between my 
> equillibration run and my actual simulation, and I'm wondering if this is 
> normal. For comparison, I ran a couple small (meaningless) simulations where 
> the only difference was the collection of free energy information and Gromacs 
> slows down by a factor of 39. I had been under the impression that I would be 
> able to do each simulation in just under an hour but now it looks like it 
> will take the better part of two days, which is too much. I'll just have to 
> run shorter or fewer simulations if I can't improve that, but I'm hoping I'm 
> just doing something wrong. I'm essentially using modified versions of the 
> .mdp file I found for this tutorial: 
> http://www.alchemistry.org/wiki/GROMACS_4.6_example:_Direct_ethanol_solvation_free_energy.
>  I changed things like turning off the pressure coupling, changing the 
> temperature, etc. The settings for free energy calculations are unchanged. Is 
> the calculation of dh/dl 
 re
>  ally that expensive, or is this abnormal?
>
> Thank you for the help as always. Regards,
> Nathan H.
>
> ----- Original Message -----
> From: "Michael Shirts" <mrshi...@gmail.com>
> To: "Discussion list for GROMACS users" <gmx-us...@gromacs.org>
> Cc: "gromacs org gmx-users" <gromacs.org_gmx-users@maillist.sys.kth.se>
> Sent: Tuesday, October 6, 2015 3:05:38 PM
> Subject: Re: [gmx-users] Free Energy of Liquid Water
>
> For a pure fluid, G  = N \mu.  And \mu = (dG/dN)_(T,P).  So you only
> need to change one molecule to ideal gas to get the change in free
> energy. The free energy of transfer of water from liquid to gas is
> indeed the free energy of solvation of one water molecule in bath of
> water.  So there's a reason why you're just finding tutorials of
> solvation free energies!
>
> On Thu, Oct 1, 2015 at 10:44 PM, Nathan K Houtz <nho...@purdue.edu> wrote:
>> Hi everyone,
>>
>> I would like to use Gromacs to do Thermodynamic Integration (TI) from liquid 
>> water (TIP4P model) to an ideal gas, to find the relative free energy. To do 
>> this, I believe  one generally integrates above the critical point by 
>> increasing the temperature above the critical temperature and then relaxing 
>> the pressure until the system is a diffuse gas. The mdp options 
>> documentation is helpful, and I went through an ethanol solvation tutorial, 
>> but there doesn't appear to be a "pressure-lambda" or a "volume-lambda" 
>> option that I could use to do the second part. How can I get Gromacs to 
>> calculate the dh/dl derivative while relaxing the pressure?
>>
>> In addition, all of the tutorials I found for thermodynamic integration were 
>> for finding solvation free energies. The coulomb and VDW forces are 
>> essentially changed from "completely on" to "completely off". But in my 
>> case, I'd like to change the temperature and pressure between two nonzero 
>> values. I don't want to begin my simulation at 0K and 0atm, but lambda 
>> *must* go from 0 to 1. How can I define both starting and ending points for 
>> the temperature and pressure (or volume, or density)?
>>
>> Thanks for your help!
>> Nathan H.
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