Hi, I'm fairly new to GTK (using version 2.24), and I'm wondering if I can move a widget (partly) outside the area of a window and still have it displayed.
Consider the following code, where I've tried to use a GtkFixed to position a label partly outside the window: ========== int main(int argc, char* argv[]) { gtk_init(&argc, &argv); GtkWidget* window = gtk_window_new(GTK_WINDOW_TOPLEVEL); gtk_window_set_default_size(GTK_WINDOW(window), 320, 240); gtk_container_border_width(GTK_CONTAINER(window), 10); gtk_widget_show(window); GtkWidget* fixed = gtk_fixed_new(); gtk_widget_set_has_window(fixed, TRUE); // Doesn't help gtk_container_add(GTK_CONTAINER(window), fixed); gtk_widget_show(fixed); GtkWidget* label = gtk_label_new("Hello World"); // y = 238 should position the label partly outside the window gtk_fixed_put((GtkFixed*) fixed, label, 0, 238); gtk_widget_show(label); gtk_main(); return 0; } ========== This is how I want it to look: ----------------------- | | | | | | | | |-------------- | -| |-------- | | -------------- And this is how it actually looks: ----------------------- | | | | | | |-------------- | || | | || | | |-------------- | ----------------------- As you can see from the comments, I already tried to use gtk_widget_set_has_window(fixed, TRUE), but it didn't do the trick. How can I do this?
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