--- On Mon, 2/13/12, suzuki toshiya <mpsuz...@hiroshima-u.ac.jp> wrote:
> Ahhhh... 10005 is hexadecimal expression of UCS-4 value? If > so, U+10005 > is a character in "LINEAR B SYLLABLE B001 DA". And, I'm not > sure how > "\uXXXX" expression should bet used for the codepoints out > of BMP at present. > For first trial, I recommend to use PUA codepoints in BMP, > U+E000 - U+F8FF, > to check if "PUA" is the root of trouble, or non-BMP is the > root of trouble. I tried with F09B and it worked fine. Yes, 10005 is the hexadecimal value I gave you. I just used one of the random empty slots to test this. I am just trying to understand how I can choose a random code, map a glyph to that code and then display the glyph by invoking it from a C program that is based on gtk. Does pango simply load the font file and pull up a glyph based on whatever value I feed it? Can I bypass the gtk function and directly deal with pango or is this not possible? -Ferdinand _______________________________________________ gtk-i18n-list mailing list gtk-i18n-list@gnome.org http://mail.gnome.org/mailman/listinfo/gtk-i18n-list
