Xu Qiang wrote:
> KC wrote:
>> I don't know any command which can report your login shell for you,
>> but you can easily write one yourself by C language, just call
>> getusershell() as following:
>>
>>
>> #include <stdio.h>
>> #include <stdlib.h>
>> #include <unistd.h>
>>
>> int main (int argc, char *argv[])
>> {
>> printf("%s\n", getusershell());
>> exit(0);
>> }
>
> But this test output "/bin/sh". If it is C shell, it should output
> "/bin/csh", right? What shell is this?
Through "man getusershell", I got to know that this function just reads the
next line of the file "/etc/shells" (opening the file if necessary).
The content of that file in my machine is:
-----------------------------------------------------------------
# $FreeBSD: src/etc/shells,v 1.5 2000/04/27 21:58:46 ache Exp $
#
# List of acceptable shells for chpass(1).
# Ftpd will not allow users to connect who are not using
# one of these shells.
/bin/sh
/bin/csh
/bin/tcsh
-----------------------------------------------------------------
And I modified your code as:
-----------------------------------------------------------------
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main (int argc, char *argv[])
{
printf("%s\n", getusershell());
printf("%s\n", getusershell());
printf("%s\n", getusershell());
exit(0);
}
-----------------------------------------------------------------
The output is just the 3 lines of shell names in /etc/shells. So I gather that
it can't be used to determine the current shell one is using.
But your advice of looking into the file /etc/passwd is good and useful.
Thank you very much,
Regards,
Xu Qiang
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