On Fri, 2005-06-17 at 08:50 -0400, Dan Winship wrote:
> On Fri, 2005-06-17 at 13:26 +0300, Alexandros Frantzis wrote:
> > Hello,
> >
> > after clicking on a Gtk.Button, I desensitize it so that I can't click
> > it again until an (asynchronous) operation finishes. The problem is that
> > when the operation finishes and I make the button sensitive again, the
> > button can't be clicked immediately! I must first move the mouse cursor
> > outside the button and then in again before I am able to click.
> >
> > Is there way around this?
>
> No, this is an old gtk bug
> (http://bugzilla.gnome.org/show_bug.cgi?id=56070). It's not easy to fix
> the way that gtk currently works.
>
After I playing around a bit, I have found a quick and dirty way to make
the button act as expected: hide and immediately show the button after
making it sensitive. I don't know the amount of overhead this incurs but
I think its small enough for normal buttons and usage. At least I can
have correct button behaviour until the bug gets fixed in gtk+ (if
ever).
The whole thing can be done manually right after setting
button.Sensitive to true, or in a StateChanged handler as in the example
below.
I hope this is useful,
Alexandros
---- Code Start ----
using System;
using Gtk;
class ButtonTest
{
Window win;
Button button;
public static void Main(string[] args)
{
Application.Init();
new ButtonTest();
Application.Run();
}
public ButtonTest()
{
win = new Window("Button Test");
win.DeleteEvent += OnWindowDeleteEvent;
button=new Button("Click me");
button.Clicked += OnButtonClicked;
button.StateChanged += OnButtonStateChanged;
win.Add(button);
win.ShowAll();
}
void OnButtonClicked(object o, EventArgs args)
{
button.Sensitive = false;
Console.WriteLine("Click!");
GLib.Timeout.Add(1000, OnTimeoutExpired);
}
bool OnTimeoutExpired()
{
button.Sensitive = true;
return false;
}
void OnButtonStateChanged(object o, StateChangedArgs args)
{
StateType prevState = args.PreviousState;
if (prevState == StateType.Insensitive
&& button.State == StateType.Normal) {
button.Visible=false;
button.Visible=true;
}
}
void OnWindowDeleteEvent(object o, EventArgs args)
{
Application.Quit();
}
}
---- Code End ----
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