I agree with you, it is too dark inside a dog to
read... But riddle me this--why do longer snow skis
make you go downhill faster? Wouldn't more contact
patch produce more friction and slow you down? Where
is the "normal" force in your equation? When you
spread the weight (a constant, at least before
breakfast) over a larger surface area, you decrease
the "normal" force--the force that multiplies the
coefficient to get traction.
I'm going to try the stock sizes my next set, even the
130 front (I'll just have to work out harder). I do
believe the 180's flat spot quicker, at least here in
Florida, where the cloverleafs are to few. I like the
Azarro's pretty much, but they don't have a 130 front
and I got the shakes back pretty early and they wander
a bit over 120...
Also, I never disagree with BOB ;)
Kevin, who must have taken physics inside the dog
--- Greg Christopher <[EMAIL PROTECTED]> wrote:
> ** Reply to message from [EMAIL PROTECTED]
> on Fri, 12 May 2000 14:50:24 -0400 (EDT)
>
> Actually,
> I did take physics once. No make that twice. :)
>
> Force (of friction) = coefficient of static
> friction X surface area in contact
>
> or
>
> Force (of friction) = coefficient of sliding
> friction X surface area in contact
>
> In the former case, if the centripetal force of the
> bike in the turn exceeds the force
> of friction, you will start to slide. Then, the
> latter takes effect.
>
> Anyway, no way around it. Given the same compound,
> the wider tire will grip
> more, Unless it's over inflated to the point where
> the contact patch is less then
> the smaller sized tire's was when it was inflated
> properly.
>
> -Greg
>
> \|/ \|/ Greg Christopher
> | | [EMAIL PROTECTED]
>
> ICQ: 4997683
> PAGER: http://wwp.mirabilis.com/4997683
> [EMAIL PROTECTED]
>
>
> Outside of a dog, books are man's best friend.
> (inside of a dog, it's too dark to read.)
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