I need to return the value.

This code is working:

def login(hash)
    hash.each_pair do |key, val|
  "#{key} ->#{val}"
  return  "dd#{key} ->#{val}"
    end
end

Thanks for your efforts to help me.




On Sep 28, 9:27 pm, Rhett Sutphin <[email protected]> wrote:
> Hi Harald,
>
> On Sep 28, 2009, at 4:09 AM, harald wrote:
>
>
>
>
>
> > Thank you for your fast reply. I do not get this to work. Should it
> > work?
> > I have haml (2.2.3) installed if that make any difference?
>
> > controller.rb:
>
> > def func(hash)
> >    hash.each_pair do |key, val|
> >        puts "#{key} ->#{val}"
> >    end
> > end
>
> > view.haml:
>
> > %p #{func({"animal" => true, "number" => 5})}
>
> This view is asking for a p tag wrapped around the string  
> representation of the return value of func.  As written, func returns  
> the input hash.  Try something like this:
>
> def func(hash)
>    hash.collect do |k, v|
>      "#{k} -> #{v}"
>    end.join("<br>")
> end
>
> It will return "animal -> true<br>number -> 5" for your sample input.
>
> Rhett
>
>
>
>
>
> > Returns:
>
> > number ->5 animal ->true
> > number5animaltrue
>
> > On Sep 28, 4:33 pm, Nathan Weizenbaum <[email protected]> wrote:
> >> I think the example you gave should work, but there are a few cases  
> >> where
> >> the Haml parser will fail to parse Ruby interpolation. The  
> >> following, for
> >> example:
>
> >>     foo #{"bar}"}
>
> >> This is because Haml doesn't do any parsing of the Ruby code except  
> >> to try
> >> to make sure brackets are balanced, so brackets within Ruby strings  
> >> will be
> >> counted as Haml brackets. At some point, Haml may try to do some  
> >> basic Ruby
> >> lexing to fix this in more cases, but that's pretty difficult to  
> >> get right.
>
> >> On Mon, Sep 28, 2009 at 12:56 AM, harald <[email protected]> wrote:
>
> >>> I have just start using haml but have some problems to understand  
> >>> how
> >>> to escape a ruby hash.
>
> >>>  like this one for example:
>
> >>> #{func({"animal" => true, "nummber" => 5})}
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