What do you mean, "doesn't work"? What's the specific error you're getting?

@function does not yet have documentation written. Everything else should be
in the Changelog and the Reference.

On Mon, Jan 31, 2011 at 9:30 AM, abierbaum <abierb...@gmail.com> wrote:

> I just tried this with the Sass 3.1 and I can't assign the result to a
> variable.
>
> ie, something like this works:
>
> p
> {
>  color: contrast_color($my_color)
> }
>
> But like this doesn't:
>
> $text_color: contrast_color($my_color)
>
> p
> {  color: $text_color; }
>
>
> Is this a bug?
>
> -Allen
>
>
> On Jan 28, 4:21 pm, Nathan Weizenbaum <nex...@gmail.com> wrote:
> > Use Sass 3.1 ;-).
> >
> > The syntax is thus:
> >
> > @function contrast_color($color, $contrast: 100%) {
> >  @if (lightness($color) > 50) { @return darken($color, $contrast) }
> >  @else { @return lighten($color, $contrast) }
> >
> >
> >
> >
> >
> >
> >
> > }
> > On Fri, Jan 28, 2011 at 2:02 PM, abierbaum <abierb...@gmail.com> wrote:
> > > Thanks.  I think I can make this work in some of my cases.
> >
> > > Now the next step though.  What I really want is a way to define a
> > > method in SASS that would do this.
> >
> > > Ex:
> >
> > > @mixin contrast_color($color, $contrast: 100%) {
> > >  @if (lightness($color) > 50) { darken($color, $contrast) }
> > >  @else { lighten($color, $contrast) }
> > > }
> >
> > > Then:
> >
> > > $base_color2: contrast_color($base_color)
> > > $widget_color2: contrast_color($widget_color)
> >
> > > Basically make a bunch of little helper methods like this that can
> > > assist in creating derived color variables and values.
> >
> > > Is this possible?  (my guess is that someone will say 'use Sass
> > > 3.1' :)
> >
> > > -Allen
> >
> > > On Jan 27, 2:49 pm, Chris Eppstein <ch...@eppsteins.net> wrote:
> > > > Hmm. The presence of !default makes this hard to do like you'd
> expect.
> >
> > > > In sass 3.1 there's a new function called if() that you can use like
> so:
> >
> > > > $base_text_color: if(lightness($base_bg_color) > 50, black, white)
> > > !defalut;
> >
> > > > if you can't/won't upgrade to the alpha version this is a
> (non-elegant)
> > > work
> > > > around:
> >
> > > > $base_text_color: false !default;
> >
> > > > @if not $base_text_color {
> > > >   @if (lightness($base_bg_color) > 50)
> > > >   { $base_text_color: black; }
> > > >   @else
> > > >   { $base_text_color: white; }
> >
> > > > }
> >
> > > > Chris
> >
> > > > On Thu, Jan 27, 2011 at 12:40 PM, abierbaum <abierb...@gmail.com>
> wrote:
> > > > > Is it possible to use an if conditional to set the default value
> for a
> > > > > variable in SASS?
> >
> > > > > I want to do something like this but I can't figure out a way to
> get
> > > > > it to work.  It looks like if's are only good for CSS blocks, not
> > > > > variable assignment.
> >
> > > > > $base_bg_color:  rgba(238, 238, 238, 0);
> >
> > > > > @if (lightness($base_bg_color) > 50)
> > > > > { $base_text_color: black !defalut; }
> > > > > @else
> > > > > { $base_text_color: white !default; }
> >
> > > > > Thanks,
> > > > > Allen
> >
> > > > > --
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