Thanks, I sent request previously to you but I have done it. Ha. ----- Original Message -----
From: "jeff saremi" <jeffsar...@hotmail.com> To: haproxy@formilux.org Sent: Tuesday, March 24, 2015 8:52:20 AM Subject: RE: How can i get haproxy reload its configuration > Subject: Re: How can i get haproxy reload its configuration > From: Vincent > Bernat > Date: 2015-03-24 12:07:34 > Message-ID: 87619q61kp.fsf () zoro ! > exoscale ! ch > � 24 mars 2015 07:45 -0400, jeff saremi  : > > #!/bin/sh > > > pidfile=/data/haproxy.pidhaproxy -db \ > > -f /haproxy-1.5.8/haproxy.cfg -p > $pidfile \ > > -sf $(cat $pidfile) > The shell does variable substitution > first, then execute the > line. Hence, $pidfile is expanded to "", not to > "/data/haproxy.pid". Put > pidfile=... on its own line. > -- > I'll burn my > books. > -- Christopher Marlowe Sorry that was just how my email got through. > Those are separate lines. So here it is again: #!/bin/sh > pidfile=/data/haproxy.pid haproxy -db \ -f /haproxy-1.5.8/haproxy.cfg -p > $pidfile \ -sf $(cat $pidfile) What i'm wondering is how this could have ever > worked? since the "$(cat $pidfile) and the creation of the $pidfile are both > on the same line. Is it possible that when the pidfile is concatenated for > the sake of "-sf" the file does not exist or contains old pids?
