wow! that is huge. Can I ask your source for the calculation in case my
boss wants to verify the data?
----- Original Message -----
From: "nobozoz" <[EMAIL PROTECTED]>
To: "The Hardware List" <hardware@hardwaregroup.com>
Sent: Thursday, July 20, 2006 5:02 PM
Subject: RE: [H] Odds calculator
Your chance of drawing 12 white balls consecutively without drawing a
single
red ball is about 1 in 15,879,054.
Odds_of_success = 1 / [ ((68-0)/(254-0)) * ((68-1)/(254-1)) * ... *
((68-(n-1))/(254-(n-1)) ] ; where n=12 samples.
_jim
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Veech
Sent: Thursday, July 20, 2006 1:35 PM
To: The Hardware List
Subject: [H] Odds calculator
I need to figure out the odds, or probability, of something happening.
Say there are 254 ping pong balls are mixed in a bag where 68 of them are
red and the other 186 are white. So, 27% of the balls are red. Someone
who
is blindfolded reaches into the bag twelve times and selects one ping pong
ball each time. What are the odds that all 12 ping-pong balls will be
white?
can anyone point me to an odds/probability calculator that will help me
establish the percentages on this? Or is anyone adept at this type of
calculation that can answer this question?
thanks
